For Loop

Question

Lu 2012-5-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39896-for-loop

Hi everybody!!

I´m trying to do a simple loop that looks like this:

for t = 1 : 1 : 5
    [k_hat, b_T, values] = E_Test(y(t:1800+t-1), n_0);
    a(:)=k_hat(t);
end

I just want that for every t, the variable "a" stores the variable k_hat but it is not working. I get the following error: Attempted to access k_hat(2); index out of bounds because numel(k_hat)=1.

If instead I try a(t)=k_hat; it just gives me one value of k_hat instead of 5 values. Could you please give me a hint on what am I doing wrong here?

Thank you so much!

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Honglei Chen 2012-5-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39896-for-loop#answer_49522

在 MATLAB Online 中打开

Apparently your k_hat is a scalar. It is probably changing in each iteration because the t you passed into E_Test is different. You can try the following in the loop

[k_hat(t), b_T, values] = E_Test(y(t:1800+t-1), n_0);