Matrix Dimensions do not agree?
显示 更早的评论
Trying to figure out why this for loop isn't working. Both fz and lsFX are 1x7 arrays, so I don't get why I'm getting the error matrix dimensions must agree
lsFX = zeros(1,7);
fz = 0.2e+03:0.2e+03:1.4e+03;
sr = -0.26:0.001:0.26;
for i=1:7
lsFX(1,i) = fz.*D.*sin(C.*atan((B.*(sr+.045)-E.*(B.*(sr+.045)...
-atan(B.*(sr+.045))))))-400;
end
采纳的回答
Geoff Hayes
2018-5-9
Michael - but sr is
sr = -0.26:0.001:0.26;
which is 1x521 which is the size of
sin(C.*atan((B.*(sr+.045)-E.*(B.*(sr+.045)...
-atan(B.*(sr+.045))))))-400
So when you are then multiplying that result by fz which is the 1x7...and so the error message makes sense.
3 个评论
Jan
2018-5-9
[MOVED from answer section] Michael Jacobson wrote:
oh sorry, I completely forgot about sr. How would I go about plotting this then? I need sr to be that many points so it smooths out the curve, but I also only want to plot 7 of those curves
@Michael Jacobson: Please post comments in the section for comments, not as answers. Thanks.
Geoff Hayes
2018-5-10
Michael - so you want to multiply each of the seven values in fz against all of the elements in sr? Could you not transpose fz to get a 7x1 matrix and then multiply that by the sr, the 1x521, to get a 7x521 result?
Michael Jacobson
2018-5-10
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
