How can I fix "Not Enough Input Arguments" error in this Script?
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Input:
t = 0:pi/50:10*pi;
x = (1/2)*(sin(2*t))+1;
y = (1/2)*(cos(2*t))+1;
z = 2*t;
plot3(x,y,z,t,'r','LineWidth',3)
Output:
Error using plot3
Not enough input arguments.
Error in testfunc (line 6)
plot3(x,y,z,t,'r','LineWidth',3)
11 个评论
t = 0:pi/50:10*pi
x = (1/2)*(sin(2*t))+1;
y = (1/2)*(cos(2*t))+1;
z = 2*t;
figure(2);
plot3(x,y,z,'r','LineWidth',3)
Stephen23
2018-6-20
@Tom Keaton: please show us the complete error message. This means all of the red text.
OCDER
2018-6-20
Code works for me without error. Is there more to it?
Tom Keaton
2018-6-20
编辑：Tom Keaton
2018-6-20
Tom Keaton
2018-6-20
Geoff Hayes
2018-6-20
编辑：Geoff Hayes
2018-6-20
Tom - which version of MATLAB are you using? If you look at that the documentation for that version (call doc plot3 from the command line) does your code satisfy the documentation description (in particular the signature for plot3)?
Note that the online documentation is for the most recent version of MATLAB (you can find archived versions though) so it may conflict with whatever version you have.
OCDER
2018-6-20
@sophia's code worked for me.
plot3(x,y,z,t,'r','LineWidth',3)
^ ^ your code has an extra t or z input.
Maybe Mathworks could change the error message to something like this:
Error using plot3
Incorrect number of input arguments.
So what do you expect a 3D plot will do with 4 dimensions of data - (x, y, z, t)? Maybe you need another plot, or a video perhaps?
Tom Keaton
2018-6-20
Greg
2018-6-21
"Not enough input arguments" is the correct error message because plot3 allows indefinite triplets of x,y,z inputs. Therefore, it thinks "t" is the first dimension of the second triplet, meaning 2 more inputs must follow.
OCDER
2018-6-21
@Tom, glad it worked!
@Greg, I guess that explains why Mathworks put that error message. But, "Incorrect number of input arguments" INCLUDES "Not enough input arguments" AND "Too many input arguments". In this case, there was too many input arguments, which was the opposite of "not enough input arguments" - this could make debugging a little confusing.
Greg
2018-6-21
Maybe you're right. Personally, MATLAB's documentation makes 100% perfect sense to me, so I just look up the calling syntax and fix it. It's probably the single most prominent reason I'm proficient with MATLAB - my brain just works exactly the way the documentation is laid out. Others might not be so lucky.
回答（1 个）
KSSV
2018-6-21
t = 0:pi/50:10*pi;
x = (1/2)*(sin(2*t))+1;
y = (1/2)*(cos(2*t))+1;
z = 2*t;
plot3(x,y,z,'r','LineWidth',3)
You need not plot t here. plot3 takes only three inputs of data i.e (x,y,z).
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2018-6-20
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