Removing elements from an Array

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CharlesB
CharlesB 2018-6-22
评论： Jan 2018-6-22
I have two arrays:
A = [0, 1]; and B = [0, 1, 3, 1, 4, 5, 6];
I want to compare the first element of A to the first 3 elements of B and the second element of A to the next 4 elements of B. If the elements of A are equal I delete it from B. So in simple:
if (A(1) == B(1:3))
delete A(1) from B
Similarly
if (A(2) == B(4:7))
delete A(2) from B
Is there any way I can do this without having to enter the indices in a hard coded manner?
So in the end B should have the following elements:
B = [1, 3, 4, 5, 6];
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CharlesB
CharlesB 2018-6-22
Sorry for not being clear the first array A will always have elements in the following sequential order 0, 1, 2 ..... The second Array B will always have an element of B so B can be [0,1,2, 0,1, 3, 1,2,5] and B has to become [1,2, 0,3, 1,5] as I removed the elements of B after comparing them as I explained above. The wanted outputs for B1 = [1,2, 0, 2]; For B2 = [2,3]; For B3 = [1,1,2, 2]. In this case I compared the elements of A for every 3 elements of B. In the above example I compared A(1) to the first 3 elements of B and A(2) to the next 4 elements of B. The comparison between 1 element of A to the elements of B can vary. What does not change is the sequential elements of A they will always b 0, 1, 2, 3,... Please stick to my question as it will get even more confusing.

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KSSV
KSSV 2018-6-22
编辑：KSSV 2018-6-22
A = [0, 1];
B = [0, 1, 3, 1, 4, 5, 6];
C{1} = B(1:3) ;
C{2} = B(4:end) ;
for i = 1:2
C{i}(C{i}==A(i))=[] ;
end
cell2mat(C)

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