Trying to break apart date string
显示 更早的评论
I have a table with a column that has a large string for the date, I want to isolate certain digits and separate them for example if I have date = 2.016010100000000e+11 I want yyyy = date(1:4) MM = date(5:6) dd = date(7:8) HH = date(9:12)
The only problem is that I want to do this for the entire table, is there a way to? Thank you
1 个评论
采纳的回答
Stephen23
2018-6-29
>> val = 2.016010100000000e+11;
>> str = sprintf('%u',val)
str = 201601010000
>> vec = datevec(str,'yyyymmddHHMM')
vec =
2016 1 1 0 0 0
3 个评论
Cameron Power
2018-6-29
编辑：Cameron Power
2018-6-29
"when it was recorded no delimeters were used in the dating,..."
That doesn't matter, we can handle that!
"...is there a way to implement this to fix every date in the table(every date is in this exact format)?"
One option would be to import the data properly to start with, using either readtable or textscan. Both of these have formats for reading dates, which is explained in their help, so I will not bore you with that here.
As an alternative you could simply import as numeric (e.g. using csvread), convert the first column to a character matrix, and then use datevec:
>> mat = csvread('aaab-dbase-2016-04-21.csv');
>> chr = num2str(mat(:,1));
>> chr(1:10,:)
ans =
201511180800
201511180810
201511180820
201511180830
201511180840
201511180850
201511180900
201511180910
201511180920
201511180930
>> dtv = datevec(chr,'yyyymmddHHMM');
>> dtv(1:10,:)
ans =
2015 11 18 8 0 0
2015 11 18 8 10 0
2015 11 18 8 20 0
2015 11 18 8 30 0
2015 11 18 8 40 0
2015 11 18 8 50 0
2015 11 18 9 0 0
2015 11 18 9 10 0
2015 11 18 9 20 0
2015 11 18 9 30 0
dtv is a numeric matrix: the first column is the year, the second column the month, etc.
Cameron Power
2018-6-29
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Dates and Time 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
