I need to map a binary array to 2 differnet values corresponding to 0 & 1

2018 6 29
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更新时间：2018 6 30
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A= zeros(320,320); A(60:180,60:180)=1;
lets say I wanna make all 1's = 2+3i and all 0's equals to 8-4i.
What would be the syntax to map them to corresponding values. Thanks

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dpb
dpb 2018-6-29
编辑：dpb 2018-6-30

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One of a zillion ways...
C=complex(2*ones(size(A)),3*ones(size(A)));
C(C==0) = 8-4i;
Another less "deadahead" but one-liner...
C=interp1([0 1],[8-4i 2+3i],A,'nearest');
ADDENDUM
A variation on the latter is simple lookup...requires the temporary vector, though.
v=[8-4i 2+3i]; % the values
C=v(A+1); % convert logical to array indices

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