How to count the number of times a value from a vector exceeded an interval?

Question

Stergios Verros 2018-8-3

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回答： Stergios Verros 2018-8-6

Dear all,

I have this vector r = [1 2 4 5 6 3 2 7] and I want to count how many times each value exceeds the interval from 4-5. More detailed, after r(5) it should count 1, after r(6) it should count 2, after r(7) it should count also 2 because it counted it before since the previous value is lower than 4 and finally after r(8) it should count 3.

Thank you very much.

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Jan 2018-8-5

@Stergios Verros: It would help to understand your question, if you post the wanted output for the example input also.

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Answer 1

Rik 2018-8-3

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编辑：Rik 2018-8-3

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The rules you want are a bit unclear, but if I understand them correctly, the code below should do what you want. If not, please give the desired output as a vector, not as text.

r = [1 2 4 5 6 3 2 7];
range=[4 5];
%Mark the positions exceeding the upper value:
L2=r>range(2);%The value should be greater than the bound
L2=L2&~[true L2(1:end-1)];%The previous value should not
%Do the reverse for the lower bound
L1=r<range(1);
L1=L1&~[false L1(1:end-1)];
output=cumsum(L1|L2);

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Image Analyst 2018-8-3

编辑：Image Analyst 2018-8-3

No, not to me. Let's say r = [11 12 14 15 16 13 12 17]. What does "how many times each value exceeds the interval from 4-5" mean. It sounds like you're wanting a histogram when you say "how many times", but what's really confusing is "the interval from 4-5". So, for my example r, do you want