How to spread elements in a cell based on vector?
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Dear all, I have cell b12 with number of elements. R is the first element after the value in vector D1. X is all values after the first element in R, however, X value does not give me the right elements. it only shows the first value after the first value in R? I appreciate if someone help me with this issue.
b12={[3,282,103,271,123,1],[3,282,103,280,260,9],[3,282,55,52,90,12],[3,282,103,280,76,13],[3,282,195,255,23]};%,[3,282,249,143,34],[3,282,103,52,90,41],[3,282,103,280,45],[3,282,103,52],[3,282,195,255,58],[3,282,103,52,63],[3,282,195,73],[3,282,103,280,76],[3,282,249,117,82],[3,282,249,84],[3,282,103,52,90],[3,282,249,143,93],[3,282,108,100],[3,282,103],[3,282,108],[3,282,103,280,110],[3,282,249,117],[3,282,103,271,123],[3,282,103,280,76,125],[3,282,249,143,126],[3,282,108,127],[3,282,128],[3,282,103,52,90,41,134],[3,282,249,143],[3,282,103,280,260,184],[3,282,195],[3,282,103,280,260,197],[3,282,216],[3,282,103,52,217],[3,282,103,280,222],[3,282,103,52,224],[3,282,249,239],[3,282,103,52,90,41,245],[3,282,249],[3,282,103,280,110,254],[3,282,195,255],[3,282,103,280,260],[3,282,103,280,222,262],[3,282,103,271],[3,282,103,280],[3,282],[3,282,103,280,260,296]}
%D1 = many numbers but on here I put only 2 elements.
D1=[282,55];
N = numel(b12);
R = cell(1,N);
X = cell(1,N);
for k = 1:N
idx = ismember(b12{k},D1);
idx = [false,idx(1:end-1)];
if any(idx)
R{k} = b12{k}(find(idx,1,'first'));
end
idx = [false,idx(1:end-1)];
if any(idx)
X{k} = b12{k}(find(idx,1,'first'));
end
end
%Expected results:
R={103,103,55,103,195}
X={271,123,1,280,260,9,52,90,12,280,76,13,195,255,23}
采纳的回答
the cyclist
2018-8-6
For X, I think you want something like
X{k} = b12{k}(find(idx,1,'first')+2:end);
b12={[3,282,103,271,123,1],[3,282,103,280,260,9],[3,282,55,52,90,12],[3,282,103,280,76,13],[3,282,195,255,23]};
D1 = [282,55];
ND1 = numel(D1);
R = cell(1,ND1);
X = cell(1,ND1);
for nd = 1:ND1
R{nd} = cellfun(@(x)x(find(x==D1(nd),1)+1),b12,'Uniform',false);
X{nd} = cell2mat(cellfun(@(x)x(find(x==D1(nd),1)+2:end),b12,'Uniform',false));
end
4 个评论
laith Farhan
2018-8-6
编辑：laith Farhan
2018-8-6
the cyclist
2018-8-6
Sorry, I misunderstood how you defined your index. My suggestion should be
X{k} = b12{k}(find(idx,1,'first'):end)
Your code is just grabbing one value. Mine is getting all the values until the end.
the cyclist
2018-8-6
Also, it was not clear to me whether you wanted each value of R and X in its own element of the cell array, or all combined into one long vector. Your "expected result" shows them as one long vector, but your code has separate cells.
laith Farhan
2018-8-6
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