How to spread elements in a cell based on vector?

Question

laith Farhan 2018-8-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/413734-how-to-spread-elements-in-a-cell-based-on-vector

评论： laith Farhan 2018-8-6

Dear all, I have cell b12 with number of elements. R is the first element after the value in vector D1. X is all values after the first element in R, however, X value does not give me the right elements. it only shows the first value after the first value in R? I appreciate if someone help me with this issue.

b12={[3,282,103,271,123,1],[3,282,103,280,260,9],[3,282,55,52,90,12],[3,282,103,280,76,13],[3,282,195,255,23]};%,[3,282,249,143,34],[3,282,103,52,90,41],[3,282,103,280,45],[3,282,103,52],[3,282,195,255,58],[3,282,103,52,63],[3,282,195,73],[3,282,103,280,76],[3,282,249,117,82],[3,282,249,84],[3,282,103,52,90],[3,282,249,143,93],[3,282,108,100],[3,282,103],[3,282,108],[3,282,103,280,110],[3,282,249,117],[3,282,103,271,123],[3,282,103,280,76,125],[3,282,249,143,126],[3,282,108,127],[3,282,128],[3,282,103,52,90,41,134],[3,282,249,143],[3,282,103,280,260,184],[3,282,195],[3,282,103,280,260,197],[3,282,216],[3,282,103,52,217],[3,282,103,280,222],[3,282,103,52,224],[3,282,249,239],[3,282,103,52,90,41,245],[3,282,249],[3,282,103,280,110,254],[3,282,195,255],[3,282,103,280,260],[3,282,103,280,222,262],[3,282,103,271],[3,282,103,280],[3,282],[3,282,103,280,260,296]}
%D1 = many numbers but on here I put only 2 elements.
D1=[282,55];
      N = numel(b12);
      R = cell(1,N);
      X = cell(1,N);
      for k = 1:N
          idx = ismember(b12{k},D1);
          idx = [false,idx(1:end-1)];
          if any(idx)
              R{k} = b12{k}(find(idx,1,'first'));
          end
          idx = [false,idx(1:end-1)];
          if any(idx)
              X{k} = b12{k}(find(idx,1,'first'));
          end
      end
      %Expected results:
      R={103,103,55,103,195}
      X={271,123,1,280,260,9,52,90,12,280,76,13,195,255,23}

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

the cyclist 2018-8-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/413734-how-to-spread-elements-in-a-cell-based-on-vector#answer_331737

在 MATLAB Online 中打开

For X, I think you want something like

X{k} = b12{k}(find(idx,1,'first')+2:end);

The following code vectorizes the whole thing using the cellfun function.

b12={[3,282,103,271,123,1],[3,282,103,280,260,9],[3,282,55,52,90,12],[3,282,103,280,76,13],[3,282,195,255,23]};
D1 = [282,55];
ND1 = numel(D1);
R = cell(1,ND1);
X = cell(1,ND1);
for nd = 1:ND1
    R{nd} = cellfun(@(x)x(find(x==D1(nd),1)+1),b12,'Uniform',false);
    X{nd} = cell2mat(cellfun(@(x)x(find(x==D1(nd),1)+2:end),b12,'Uniform',false));
end

4 个评论
显示 2更早的评论隐藏 2更早的评论

the cyclist 2018-8-6

Also, it was not clear to me whether you wanted each value of R and X in its own element of the cell array, or all combined into one long vector. Your "expected result" shows them as one long vector, but your code has separate cells.

laith Farhan 2018-8-6