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Need help! I keep getting the error "not enough input arguments" how do I fix this?

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Denikka Brent
Denikka Brent 2018-9-10
评论： Star Strider 2018-9-10
function drv = untitiled18(t,rv);
% small r is position
% big r is distance
mu = 3.986004*(10^5); %%unit is in km^3/s^2, and is Earth's Gravitational parameter
drv = zeros(6,1);
rx = rv(1);
vx = rv(2);
ry = rv(3);
vy = rv(4);
rz = rv(5);
vz = rv(6);
R = sqrt((rx^2)+(ry^2)+(rz^2));
% X component/ i direction
drv(1) = rv(2);
drv(2) = (-mu.*rx)/(R^3); % (vx) velocity in the x direction
% Y component/ j direction
drv(3) = rv(4);
drv(4) = (-mu.*ry)/(R^3); % (vy) velocity in the y direction
% Z component/ k direction
drv(5) = rv(6);
drv(6) = (-mu.*rz)/(R^3); % (vz) velocity in the z direction
end
  7 个评论
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Star Strider
Star Strider 2018-9-10
I agree. I doubt there are any significant differences between those versions with respect to ode45.
What line is throwing the error?
Denikka Brent
Denikka Brent 2018-9-10
Not enough input arguments.
Error in propagate_2BP22 (line 11) rx = rv(1);
Error in untitled5 (line 41) [t,rv] = ode45(propagate_2BP22, t, [rinputx, vinputx, rinputy, vinputy, rinputz, vinputz], options);
Note: I did change the name again but the callouts match so that shouldn't be an issue.

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回答（2 个）

Star Strider
Star Strider 2018-9-10
Your latest code (as you posted it in your earlier Comment), runs for me without error.
The only thing I can think of is that you have a function called ‘rv’ somewhere. To find it, run this:
q = which('rv','-all')
  2 个评论
Star Strider
Star Strider 2018-9-10
You could run your ‘propagate2BP’ function with the solved values to get some of those (I do not understand what variables those would be).
It would be easier to begin with the solved position values and use numerical differentiation one time to then get the velocity values, and two times to get acceleration.
Use the gradient (link) function to do the numerical differentiation. This will be more accurate if you define ‘t’ as:
t = linspace(0, 172800, 21681);
or something similar, to get equally-spaced solved position values.
In differentiating a matrix, gradient differentiates across both the rows and columns, and the first output is the derivative down the columns. I would do the differentiation as:
drv = gradient(rv, mean(diff(t)), 1);
Note that this differentiates all the columns, so choose the original position columns from the ‘drv’ output.

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Walter Roberson
Walter Roberson 2018-9-10
编辑：Walter Roberson 2018-9-10
The error line you post is
[t,rv] = ode45(propagate_2BP22, t, [rinputx, vinputx, rinputy, vinputy, rinputz, vinputz], options);
which is not the same as what you posted before that, which was
[t,rv] = ode45(@propagate2BP, t, [rinputx, vinputx, rinputy, vinputy, rinputz, vinputz], options);
Notice the difference between propagate2BP and @propagate2BP . You need the @ version so your propagate_2BP22 would have to be @propagate_2BP22

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