solve the binary integer (0,1) problem

2 次查看(过去 30 天)
Pero Pajo
Pero Pajo 2018-10-10
评论: Stephan 2018-10-10
Could somebody please help me?
I am trying to solve the binary integer (0,1) problem by using a function from this link https://www.mathworks.com/matlabcentral/fileexchange/6990-mixed-integer-lp
f represent six possible places where I can put measuring devices.
My f is x1 to x6 = [1 1 1 1 1 1]
My A =
[ 1 1 1 1 1 1;
1 1 1 1 1 1;
1 0 1 1 1 1;
1 0 1 1 1 1;
1 0 1 1 1 1;
0 0 1 1 1 1]
Lb [0 0 0 0 0 0] and ub [1 1 1 1 1 1 ]
M = [1 1 1 1 1 1]
B = [3 3 3 3 3 3]
And e I left the same as in example. For answer I get
Ans =
0
0.3475
0.0000
0.0000
0.0000
0.0000
However, I would like to get binary answers that will give me information about where to put measuring devices considering given constrains.
  2 个评论
Bruno Luong
Bruno Luong 2018-10-10
编辑:Bruno Luong 2018-10-10
What is "B"? There is "b" as input but not upper case. Your matrix A has duplicated row, meaning you put redundancy in the constraints, thus the problem doesn't seem to be well formulated to me.
If "B" is "b", the solutions are simply peak 3 random positions among 6.

请先登录,再进行评论。

回答(2 个)

Stephan
Stephan 2018-10-10
编辑:Stephan 2018-10-10
If you want to get binary output there should be a possibility to add integer constraints for x(1)...x(6). In combination with lower and upper bounds of 0 and 1 for all x, you would get what you want.
In the function you use this is done by defining vector M containing the indices of integer constrained variables.
M = 1:6;
If you have access to Optimization Toolbox you could also use intlinprog for this purpose.
Also follow the comments given above.
Best regards
Stephan
  1 个评论
Stephan
Stephan 2018-10-10
If the answers you got were useful for you, you can accept and/or vote for them. This is how the volunteers here earn reputation.

请先登录,再进行评论。


Pero Pajo
Pero Pajo 2018-10-10
I want to thank you all for your answers,

类别

Help CenterFile Exchange 中查找有关 Solver Outputs and Iterative Display 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by