Assignment has more non-singleton rhs dimensions than non-singleton subscripts?
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Hello, here is my code:
for f = 1:n ind(f,1) = num2cell(find(edges{f,1} == inde_x),2); in_d(f,1) = size(ind{f,:},2); indx = find(in_d ~= 0); end
I have edges matrix 9x1 cell and inde_x = 6
See the edges matrix below [6 9] [1 5] [5 6] [6 9] [6 7] [1 5] [5 9] 7 [1 7]
I'am trying to find values in inde_x = 6 in the edges matrix and ind matrix is formed as follows:
1 [] 2 1 1 [] [] 1 []
As seen above, in the edges matrix is equal to 6 in the row 6 finds the number and writes number of the index. If there is no value equal to 6, the [] sign is written but the number {8,1} does not have a value of 6, but the number 1 occurs and the following error is written:
Error in aaaaaaaaaaaaa (line 125) ind(f,1) = num2cell(find(edges{f,1} == inde_x),2);
How can I solve this problem? Thanks.
3 个评论
Jan
2018-10-22
The question is not clear. Start with formatting the code using the "{} Code" button, see How to format code in the forum.
The names of the variables ind, inde_x, in_d, indx are really confusing. I recommend to use smarter names.
The show "edge matrix" is not clear. Please use the standard Matlab syntax to define a matrix.
"1 [] 2 1 1 [] [] 1 []" This does not form a matrix. Matrix elements cannot be empty.
"As seen above, in the edges matrix is equal to 6 in the row 6 finds the number and writes number of the index" - I do not understand this sentence. I do not see this above.
"the [] sign is written but the number {8,1}" - this is not clear also. [] is the concatenation operator, not a "sign".
" and the following error is written: ..." - This is only the part of the error message, which tells, where the error occurs. The other parts matter also, which explain what the error is.
Abdullah Türk
2018-10-22
Guillaume
2018-10-22
I was going to ask why you'd use a cell array instead of a Nx2 matrix to store edges then saw that one of your edge has only one element. Why? Don't your edge describe a graph? If so all edges should have two elements. If it's a self-loop, the node should be repeated.
采纳的回答
Guillaume
2018-10-22
k = 6;
A = cellfun(@(edge) find(edge == k), edges, 'UniformOutput', false)
The loopy version of that:
k = 6;
%n unused. Never hardcode the number of elements. Ask matlab what it is with size or numel
A = cell(size(edges));
for idx = 1:numel(edges)
A{idx} = find(edges{idx} == k);
end
Note the difference between A(idx) and A{idx}. Your attempt at using num2cell show that you don't really know how to access cell arrays.
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KSSV
2018-10-22
k = 6;
n = 9;
edges{1,1} = [6 9]
edges{2,1} = [1 5]
edges{3,1} = [5 6]
edges{4,1} = [6 9]
edges{5,1} = [6 7]
edges{6,1} = [1 5]
edges{7,1} = [5 9]
edges{8,1} = 7
edges{9,1} = [1 7]
A = cell(n,1) ;
for f = 1:n
T = num2cell(find(edges{f,1} == k),2) ;
if ~isempty(T)
A(f,1) = T;
else
A(f,1) = {[]};
end
end
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