How to find the value closest to 1 from a xyz double matrix ?

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Eranja Noopehewa 2018-10-28

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https://ww2.mathworks.cn/matlabcentral/answers/426517-how-to-find-the-value-closest-to-1-from-a-x-y-z-double-matrix

评论： Eranja Noopehewa 2018-10-30

I have to find the values for k according to the following code. When I execute the following code I get a 18x12x6 double to k. From that how can I find the exact p,n and m which is corresponding a value which is closest to 1 from matrix k??

I1= 8.0742;
I2=4.85;
I3=2.4293;
for p=1:18
    for n=1:12
        for m=1:6
            k(p,n,m) = p*I1/(n*I2+m*I3);
        end
    end
end

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采纳的回答

Stephen23 2018-10-28

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https://ww2.mathworks.cn/matlabcentral/answers/426517-how-to-find-the-value-closest-to-1-from-a-x-y-z-double-matrix#answer_343808

编辑：Stephen23 2018-10-28

在 MATLAB Online 中打开

>> [~,x] = min(abs(k(:)-1));
>> [p,n,m] = ind2sub(size(k),x)
p =  6
n =  9
m =  2
>> k(p,n,m)
ans =  0.99869

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Stephen23 2018-10-30

在 MATLAB Online 中打开

Use sort instead of min, and pick as many as you want:

>> [v,x] = sort(abs(k(:)-1));
>> [p,n,m] = ind2sub(size(k),x(1:3)) % first three
p =
   6
   3
   6
n =
   9
   4
   8
m =
   2
   2
   4
>> k(p(1),n(1),m(1))
ans =  0.99869
>> k(p(2),n(2),m(2))
ans =  0.99852
>> k(p(3),n(3),m(3))
ans =  0.99852