清空筛选条件
清空筛选条件

how can i seperate the value exp(1i*2*pi*bbbb);

3 次查看（过去 30 天）
aaru sri
aaru sri 2018-11-16
评论： aaru sri 2018-11-21
x1=exp(1i*2*pi*bbbb);
d1=bb1.*exp(1i*2*pi*bbbb);
d2=abs(d1);
d3=angle(d1);
d4=exp(1i*d3); %value are not same as x1
%how can i extract the value of x1 from d1
  1 个评论
Jan
Jan 2018-11-19
Please stop posting questions by attaching them to existing threads in the section for answers. Ask new questions only by opeing new threads. Thanks.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Adam Danz
Adam Danz 2018-11-16
The question is unlcear.
Given d1 from [d1 = bb1 * exp(a)], are you asking how to get exp(a)? If so,
exp(a) = log(d1/bb1);

更多回答（3 个）

aaru sri
aaru sri 2018-11-17
i want to find the value of x1 from the d1
madhan ravi
madhan ravi 2018-11-17
syms x1 bb1 d1
isolate(d1==bb1.*x1,x1)
Bruno Luong
Bruno Luong 2018-11-17
编辑：Bruno Luong 2018-11-17
"i want to find the value of x1 from the d1"
x1 = d1/abs(d1)
if bbbb is real.
You need a major update of complex number theory.
  1 个评论
aaru sri
aaru sri 2018-11-21
d1=bb1.*exp(1i*2*pi*bbbb);
d12=abs(d1);
d13=angle(d1);
d16=d13./(2*pi);
here i m getting the change in phase at few elements ...value of d16 is same as bbbb but few values are going negative how to correct it

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by