how can i seperate the value exp(1i*2*pi*bbbb);

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aaru sri
aaru sri 2018-11-16
评论： aaru sri 2018-11-21
x1=exp(1i*2*pi*bbbb);
d1=bb1.*exp(1i*2*pi*bbbb);
d2=abs(d1);
d3=angle(d1);
d4=exp(1i*d3); %value are not same as x1
%how can i extract the value of x1 from d1
  1 个评论
Jan
Jan 2018-11-19
Please stop posting questions by attaching them to existing threads in the section for answers. Ask new questions only by opeing new threads. Thanks.

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采纳的回答

Adam Danz
Adam Danz 2018-11-16
The question is unlcear.
Given d1 from [d1 = bb1 * exp(a)], are you asking how to get exp(a)? If so,
exp(a) = log(d1/bb1);

更多回答（3 个）

aaru sri
aaru sri 2018-11-17
i want to find the value of x1 from the d1
madhan ravi
madhan ravi 2018-11-17
syms x1 bb1 d1
isolate(d1==bb1.*x1,x1)
Bruno Luong
Bruno Luong 2018-11-17
编辑：Bruno Luong 2018-11-17
"i want to find the value of x1 from the d1"
x1 = d1/abs(d1)
if bbbb is real.
You need a major update of complex number theory.
  1 个评论
aaru sri
aaru sri 2018-11-21
d1=bb1.*exp(1i*2*pi*bbbb);
d12=abs(d1);
d13=angle(d1);
d16=d13./(2*pi);
here i m getting the change in phase at few elements ...value of d16 is same as bbbb but few values are going negative how to correct it

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