Need to use cellfun for returning index of array

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Thulasi Durai Durai Samy 2012-7-9

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采纳的回答： Jan

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Hello

I need to find index for string in structures when compare with required string.

I use the following code

for i=1:numel(LD)
       if strcmp('Lam1',LD(i).Name)
            break;
       end
   end

where i = array index.

Here I will find the index for string residing in LD(:).Names

is their any easy way to find the index using cellfun

I tried like this cellfun(@strcmp,'Lam1',LD(:).Names)

should return the index, correct me I am worng.

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Jan 2012-7-9

编辑：Jan 2012-7-9

You forgot to explain the type of LD.Name: Are they strings or cell strings? And btw., is it LD.Name or LD.Names in plural? I avoid corresponding programming errors by the simple convention:

All names in singular
When it matters if a variable is a scalar entity or a list of objects: aMyObject and MyObjectList.

I do not think that this is nicer, but avoiding sources of bugs is more important, especially because useful programs tend to grow.

Thulasi Durai Durai Samy 2012-7-9

thanks for your nice comments

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Answer 1

Jan 2012-7-9

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https://ww2.mathworks.cn/matlabcentral/answers/43087-need-to-use-cellfun-for-returning-index-of-array#answer_52978

编辑：Jan 2012-7-9

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No need for cellfun or arrayfun:

index = find(strcmp('Lam1', {LD.Name}), 1);

{LD.Name} is efficient, because it creates shared data copies only - this means that the actual strings are not duplicated.

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Thulasi Durai Durai Samy 2012-7-9

ya, it works !! what actually happening in side can you brief me. why to pass 1 as argument for 'find' function.

Jan 2012-7-9

find(., 1) searchs for the first occurrence only, see help find. On one hand this is a little bit faster, if LD is really large. On the other hand it replicates the behaviour of your function, which breaks after the first occurence also.

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