Remove the slprj folder programmatically

Question

Bonpland 2018-11-21

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https://ww2.mathworks.cn/matlabcentral/answers/431142-remove-the-slprj-folder-programmatically

评论： Mostaza Con huevos 2021-2-12

There is an 'slprj' in the working directory that is from another Simulink version. Consequently, I receive the error

'The existing Simulink code generation folder in the current folder was created for a different version of MathWorks products. This project folder is not compatible with the current version. To continue you must manually remove the slprj folder and any generated code files it contains.'

when trying to compile my model. However, I do not want to manually remove the folder each time. The programmatic approach via

rmdir('slprj')

from the MATLAB command line also issues an error.

So how can I programmatically remove the 'slprj' folder?

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Bonpland 2018-11-21

That would have been my first explanation. However, manually removing this folder is possible without issues.

Mostaza Con huevos 2021-2-12

someone else can helpme whit the folder slprj all the folder.

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Answer 1

Sean de Wolski 2018-11-21

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https://ww2.mathworks.cn/matlabcentral/answers/431142-remove-the-slprj-folder-programmatically#answer_348245

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What about with the 's' option

rmdir('slprj', 's')

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Gordon Lai 2020-4-2

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The full path version of this worked for me as 'slprj' is not empty (nor is it usually).

Note: I first added it and subfolders to the MATLAB path, using

addpath(genpath(pwd))

(unsure if that is necessary)

Sean de Wolski 2020-4-2

编辑：Sean de Wolski 2020-4-2

Typically if you're calling addpath/genpath, you should be using a project. This also lets you customize code generation settings at a project level.

https://www.mathworks.com/help/matlab/matlab_prog/create-projects.html

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Answer 2

Jan 2018-11-21

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编辑：Jan 2018-11-21

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This does not solve the problem, but helps to identify the problem: Catch the error message:

[status, msg] = rmdir('slprj')
if status ~= 1
    fprintf(2, '%s\n', msg);
end

By the way, of course you can use absolute path names even on different platforms. This does not mean a hard coded path name, but that you do not rely on the current directory to be, what you expect. Remember that each timer and GUI callback can use cd to change the current directory, and rmdir('slprj') might access an unexpected folder. Better:

baseFolder = cd;  % Or even better: define it with a meaningful folder
[status, msg] = rmdir(fullfile(baseFolder, 'slprj'))
if status ~= 1
    fprintf(2, 'Folder: %s\nProblem: %s\n', ...
        fullfile(baseFolder, 'slprj'), msg);
end

Now the error message should be more useful.

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Jan 2018-11-22

编辑：Jan 2018-11-22

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@Bonpland: This sounds strange, because then the replied status must be 1, which means a successful deleting. In case of a problem, the error message written by my code would contain the name of the folder.

Even empty folders can require different privileges for deleting, so it does not matter if the subfolders are empty.

Do you have any evidence, that the current directory is what you expect it to be? Is the folder really empty, when you call rmdir or did you test this some seconds later only in the Windows Explorer - with enabled display of hidden and system files? Remember that e.g. the virus scanner might access and block the files, so what happens with a fallback method:

ready  = false;
count  = 0;
folder = fullfile(baseFolder, 'slprj');
while count < 10 && ~ready
   count         = count + 1;
   [status, msg] = rmdir(folder);
   if status == 1
      ready = true;
   else
      fprintf(2, 'Folder: %s\nProblem: %s\n...retrying...\n', ...
          folder, msg);
      pause(0.5);
   end
end
if count == 10
   fprintf(2, 'Deleting folder failed: %s\n', folder);
end

There is still a detail you did not mention, because you are not aware of it. So please post as much details as you can to give the readers a chance to see, what you do not see.

Bonpland 2018-11-22

编辑：Bonpland 2018-11-22

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Sorry, I do not unterstand what you're looking for, especially with the last paragraph of your last comment. So, let me reiterate the facts:

1) As expected, the output of your script is just a recurring

Folder: D:\dev\slprj
Problem: No directories were removed.
...retrying...

The status is '0'.

2) The folder 'slprj' may be removed manually from the MATLAB GUI or in the Windows Explorer.

3) Creating a new folder 'slprj' manually somewhere else and trying to delete it programmatically in MATLAB is also no issue.

From 1)-3) I infer that the automatic creation of the folder 'slprj' is imposing some kind of access restriction which cannot be circumvented from within MATLAB. However, this is in no way contained in the error message.

Any help would be greatly appreciated.

Jan 2018-11-29

The next question: What does "There is an 'slprj' in the working directory that is from another Simulink version" mean? Is "the other Simulink version" still running?

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Answer 3

Bonpland 2018-11-29

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https://ww2.mathworks.cn/matlabcentral/answers/431142-remove-the-slprj-folder-programmatically#answer_349537

Are there any news on this issue?

It would be good to have at least a feedback on how this problem is perceived by MathWorks.

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Jan 2018-11-29

Please do not post a pseudo-answer only to bump your question. This wastes the time of all readers. This is the public forum. If you want MathWorks to react to your question, contact them directly using the "Contact Us" link on top of this page.

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Remove the slprj folder programmatically

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