How to plot consistent data?
显示 更早的评论
Hi,
I am new to matlab. I have 2 variables T and H with 1652 cells in each. I want to plot H vs T when T is consecutively increasing for 10 values.
for eg :
let T = [9 8 7 8 9 7 6 5 4 5 6 7 8 9 10 11 12 13]
H= 1:18
i want to plot H vs T for the last 10 values of T
ie, T= [4 5 6 7 8 9 10 11 12 13]
H=[9 10 11 12 13 14 15 16 17 18]
Thanks once again !!
[EDITED, Jan] Information required to define the question exactly belongs to the question. It is not a minor comment.
THe logic i tried was:
for i= 1:length(H)-11
for k=1:10
if T(i)>T(i+k)
T(i)=NaN
T(i+k)=NaN
H(i)=NaN
H(i+k)=NaN
end
end
end
plot(T,H)
But I am not getting desired results. Any advice to improve this logic would be helpful
Thanks
2 个评论
Please read the instruction about code formatting again. It is worth to care about the forum rules and standard. If in doubt, follow the "About Matlan Answers" button or the "? Help" button, which appears, when you add a new message.
Using "matlab" as tag is meaningless in a Matlab forum, isn't it?
When I spend too much time with editing a question and merging comments, I'm not motivated to answer anymore. But here are enough other users, who will do this.
What kind of results do you desire,your code seems to be generating vectors you've written on the top,is there a problem in graph ???
采纳的回答
Andrei Bobrov
2012-7-10
T = [9 8 7 8 9 7 6 5 4 5 6 7 8 9 10 11 12 13];
a = [true,diff(T)>=0];
a(strfind(a,[0 1])) = true;
n = 10;
ii = find(conv(a+0,ones(1,n),'same') == n,n,'last') - n/2 + 1;
idx = ii:ii+n-1;
plot(T(idx),H(idx));
2 个评论
Joe Abraham
2012-7-16
Andrei Bobrov
2012-7-16
strfind only for row
eg
yourData = [9 8 7 8 9 7 6 5 4 5 6 7 8 9 10 11 12 13].';
T = yourData(:).';
a = [true,diff(T)>=0];
a(strfind(a,[0 1])) = true;
n = 10;
ii = find(conv(a+0,ones(1,n),'same') == n,n,'last') - n/2 + 1;
idx = ii:ii+n-1;
plot(T(idx),H(idx));
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
2012-7-10
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
