Is there a way to assign the 'end' value to a variable?
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Hello everyone,
this is my first question. Sorry if it's too simple or easy, but i couldn't find the answer at Google.
I was programming a simple script to locate all file names in a folder. Most of them had a similar name, with '_' character in it (ex: file_name.mat), but not all of them. I wanted only the firt part of the name, from those with '_' character.
I did something like this (is a shorter version of my code):
for i=1:length(list_of_files)
b=findstr('_',list_of_files(i).name)-1;
if isempty(b)
b='end' %That's my question
end
another_list{i}=list_of_files(i).name(1:b)
end
I know that i could just use 'length(list_of_files(i).name)' instead of 'end', but i was out of curiosity to ask about if it was possible to assign 'end' to a variable, and how?
I've already tried something like:
b=end;
b='end';
Doesn't work!
Thanks
Sergi
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采纳的回答
Steve Eddins
2012-7-10
No, you can't assign the indexing value of "end" to a variable. You have to use size, or length, or numel in order to assign the value to a variable.
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更多回答(4 个)
F.
2012-7-10
And did you try strread ??
[A, B, ...] = strread('str', 'format')
[ NameStart, NameEnd ] = strread( list_of_files(i).name, '%s_%s')
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Jan
2012-7-10
编辑:Jan
2012-7-10
for i=1:length(list_of_files)
b = strfind(list_of_files(i).name, '_') - 1; % FINDSTR is deprecated
if isempty(b)
another_list{i} = list_of_files{i}; % Curly braces!
else.name(1:b)
another_list{i} = list_of_files{i}(1:b(1));
end
end
"b(1)" considers even multiple underscores. But if an underscore appears, the file extension is cut off also, while it is kept for names without underscores.
strtok can do the conversion also. You can even avoid the loop:
another_list = strtok(list_of_files, '_');
But the file extension problem is still not addressed.
Daniel Shub
2012-7-10
While I have not verified it, I think if you really wanted to assign
b='end'
and then use it for indexing, that you could overload subsref. I cannot think of a good reason you would want to do this.
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