how to do bitxor operation of two 1*255 matrix

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moni sinha
moni sinha 2018-11-30
编辑： Greg 2018-11-30
h1 =1x255 logical
h3 = 1x255 logical
howto do bitxor of h1 and h3

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回答（2 个）

Greg
Greg 2018-11-30
编辑：Greg 2018-11-30
result = h1 | h3;
Edit: this is logical (bit) or, not xor. As posted elsewhere, simply use the xor function.
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Jan
Jan 2018-11-30
The error message is clear: The array sizes are different. Here the variables h1 (logical) and c (double) are concerned. So why do you ask for "h1 =1x255 logical, h3 = 1x255 logical"?
Greg
Greg 2018-11-30
编辑：Greg 2018-11-30
Good catch Guillaume, i kept reading or not xor.
Why are we assuming c is the second argument? The original post explicitly states h1 and h3, both are logical and same size. All following posts are new problems to the original question.

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James Tursa
James Tursa 2018-11-30
编辑：James Tursa 2018-11-30
It's not entirely clear to me what operation you really want, but if the elements of h1 and h2 represent "bits", then you could just do this:
result = (h1 ~= h2); % equivalent of xor between the elements of h1 and h2
If h1 and h2 don't have the same number of elements, then that is a different problem that you will need to fix before doing the xor operation.

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