Histogram with values above the bars
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Hello,
I got data with values form 90 to 100, and i can have decimal values like 90.4 95.3. My goal is to create an histogram with binedges (i tihnk is the proper name) with 90-91, 91-92, 92-93, etc.
A = randi([90 100],50,1);
B = rand(50,1);
C = A + B;
histogram(B(:,1),'BinWidth',1);
And I would to know how to place the on top of each bar, how many values from 90 to 91, 91 to 92, etc
Thanks for your time
采纳的回答
Steven Lord
2018-12-5
I would not depend upon the tick locations as Luna's solution does. Use the data stored in the histogram object itself instead.
Generate some sample data and create the histogram.
data = 10*rand(1,100);
x = histogram(data,'BinWidth',1);
Retrieve the locations of the edges and the heights of the bars.
E = x.BinEdges;
y = x.BinCounts;
Find the X coordinates of the center of the bars. This takes the left edge of each bar and adds half the distance to the next bar edge.
xloc = E(1:end-1)+diff(E)/2;
Put the labels 1 unit above the top of the bar center.
text(xloc, y+1, string(y))
4 个评论
Right, it works fine except string. Needed mxn char array.
text(xloc, y+1, num2str(y'))
Steven Lord
2018-12-7
That would depend which release you're using. I tried it in release R2018b and it works. I don't remember offhand when the text function started accepting string arrays.
Luna
2018-12-9
Ah OK, you are right. Mine is 2018a.
xingxingcui
2020-8-31
h = histogram('Categories',Categories,'BinCounts',N);
y = h.Values;
text(1:length(N), y+50, string(y));
更多回答（1 个）
Luna
2018-12-5
Hello Tiago,
Try this for getting labels on the top of the bars of your histogram.
data = 10*rand(1,100);
x = histogram(data,'BinWidth',1);
labels = num2str(x.BinCounts');
xt = get(gca, 'XTick');
xVals = xt - ([0 diff(xt)]/2);
xVals(1) = [];
text(xVals, x.BinCounts, labels, 'HorizontalAlignment','center', 'VerticalAlignment','bottom')
But first check your data to plot histogram there is something wrong about it:
A = randi([90 100,100,1]); % look randi function and its inputs
B = rand(50,1);
C = A + B; % check A and B have the same sizes to add
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