Selecting a particular part of a string variable

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antonet
antonet 2012-7-11
Dear all,
I have
A={'BARI 500 esd' ...
'DUR NOR 18 df '
}
I want to choose the part of the string that is up to the number that appears in each string
That is, for the above example I want to select
'BARI 500'
'DUR NOR 18'
Is there a way to do that?
thanks

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采纳的回答

Jan
Jan 2012-7-12
编辑：Jan 2012-7-12
A = {'BARI 500 esd', ...
'DUR NOR 18 df '};
B = cell(size(A));
for i = 1:numel(A)
a = A{i};
index = find(isstrprop(a, 'digit'), 1);
a = a(1:index);
index = find(~isspace(a), 1, 'last'); % hand coded STRTRIM
B{i} = a(1:index);
end
[EDITED] For your edited question:
for i = 1:numel(A)
a = A{i};
index = find(isstrprop(a, 'digit'), 1, 'last');
B{i} = a(1:index);
end

更多回答（2 个）

Matt Kindig
Matt Kindig 2012-7-12
Regular expressions might provide an easier way.
fcn = @(s) regexpi(s, '^(\D+)', 'match', 'lineAnchors'); %regex function
B = cellfun( fcn, A); %run on cell array A
B = strtrim(B); %get rid of trailing spaces
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Jan
Jan 2012-7-12
@antonet: But this was what you were asking for. Please explain "I want to select" exactly.
antonet
antonet 2012-7-12
编辑：antonet 2012-7-12
you are right. I edited my initial question . thank you and sorry

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Azzi Abdelmalek
Azzi Abdelmalek 2012-7-12
编辑：Azzi Abdelmalek 2012-7-12
A={'BARI 500 esd' 'DUR NOR 18 df '};
a=char(A);
[n,m]=size(a);w=[];
for k=1:n
v=[];testp=1;test=0;test2=0
for h=1:m
if length(regexp(a(k,h),'[0-9]'))>0
test=1,testp=0,
end
if test==0 & testp==1
v=[v a(k,h)],test2=1
elseif test==1 & test2==1
v=[v a(k,h)],test=0
else
test2=0,testp=0,test=0
end
end
w=strvcat(w,v);
end
disp(w)

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