I need to find out what this program is missing

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Aaron 2012-7-12

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/43471-i-need-to-find-out-what-this-program-is-missing

I'm trying to use this program to calculate the cos of a given(prompted) angle in degrees.

A=input('Enter angle:');
x=(pi/180)*A; 
format long
a=0;c=0;sg=1;
while 
    c=c+sg*((x^(2*a))/(factorial(2*a))); % Infinite series calculation.
    a=a+1;sg=-sg;
end
fprintf('cos = %6f',c);

I get no answer and I have to close Matlab and restart.

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Albert Yam 2012-7-12

If you are stuck in a loop. (See 'Busy' in the bottom left.) hit Ctrl+C

Ryan 2012-7-12

This should help: TUTORIAL: how to format your question with markup.

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采纳的回答

Albert Yam 2012-7-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/43471-i-need-to-find-out-what-this-program-is-missing#answer_53351

在 MATLAB Online 中打开

while [condition] %that should only be true to run the loop
   %stuff in loop
end % make sure to end the loop, but should give a warning about that

If your condition is just a constant, than your loop is always running. But your code is not 'copy/paste'-able into Matlab for us to check.

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Albert Yam 2012-7-12

在 MATLAB Online 中打开

A=input('Enter angle:');%angle in degrees 
x=(pi/180)*A; % radians 
n=input('Enter the number of places; ') 
format long 
a=0;c=0;sg=1; 
while a~=n % New condition. 
c=c+sg*((x^(2*a))/(factorial(2*a))); % Infinite series calculation. 
a=a+1;sg=-sg; 
end 
fprintf('%6f',c);

You can always just hardcode n=6, in the condition, since you said it is a 'need'. While loops need a condition, how else would it know to stop looping (your previous problem)? Unless you know exactly how many times to loop (For loop). For the '>>' on the next line,

fprintf('%6f\n',c);

Please use the {}code formatting next time. It is easier for people to copy/paste into Matlab to see what is wrong.

A=input('Enter angle:');%angle in degrees x=(pi/180)*A; % radians n=input('Enter the number of places; ') format long a=0;c=0;sg=1; while a~=n % New condition. c=c+sg*((x^(2*a))/(factorial(2*a))); % Infinite series calculation. a=a+1;sg=-sg; end fprintf('%6f',c);

Comments out everything after the A=input

Aaron 2012-7-12