flip a matrix using loops

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Ariela Glikman
Ariela Glikman 2018-12-9
评论： Stephen23 2018-12-9
hi,
im tring to flip a matrix usind withot the flip function
for ex:
[1 3 -2; -4 4 8; 7 -1 3] will cange to [7 -1 3; -4 4 8; 1 3 -2]
my script is
outFlip(i,:)= inMatrix(size(inMatrix,1)+1-i,:);

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回答（2 个）

Jan
Jan 2018-12-9
编辑：Jan 2018-12-9
Your line is correct already. Only the loop is missing:
n = size(matrix, 1);
for k = 1:n
outFlip(k,:) = inMatrix(n - k + 1, :);
end
Without the loop:
n = size(matrix, 1);
outFlip = inMatrix(n:-1:1, :);
madhan ravi
madhan ravi 2018-12-9
matrix=randi([0,4],2);
outFlip=zeros(size(matrix,1),size(matrix,2));
for i= 1:size(matrix,1)
for j=1:size(matrix,2)
outFlip(j,i)=matrix(i,j); % just swap the indices
end
end
  2 个评论
Ariela Glikman
Ariela Glikman 2018-12-9
no, i mean:
[1 3 -2; -4 4 8; 7 -1 3] will cange to [7 -1 3; -4 4 8; 1 3 -2]
madhan ravi
madhan ravi 2018-12-9
ok then:
matrix=[1 3 -2; -4 4 8; 7 -1 3];
ctr=1;
outFlip=zeros(size(matrix,1),size(matrix,2));
for i=size(matrix,1):-1:1
outFlip(i,:)=matrix(ctr,:); % just swap the indices
ctr=ctr+1;
end
outFlip

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