How to compare 5 cell arrays and get their contents in one cell array?
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Hello gyus,
I have a cell array of size 600*1 and 4 cell arrays: cell1(361*2), cell2(376*2), cell3(362*2) and cell4(351*2).
cell array(600*1) have overlap rows with all of these 4 cell arrays column1 rows;
I want to output a cell of size 600*4 with the 600 rows and 4 columns, which are the contents of the 4 cells column 2 contents if there is an overlap with their rows , if not put 0.
More specifically some rows in cell array( 600*1) may exist in all the rows of all the 4 cells or may exist in just some of them.
Inputs: cell array, cell1, cell2, cell3, and cell4
I appreciate any help plz!
Original cell:
'R-HSA-3000171:R-HSA-3000171'
'R-HSA-3000178:R-HSA-3000178'
'R-HSA-3000471:R-HSA-3000471'
'R-HSA-3000480:R-HSA-3000480'
'R-HSA-3000484:R-HSA-3000484'
cell1
'R-HSA-3000171:R-HSA-3000171' 'PDGFB'
'R-HSA-5419276:R-HSA-5419276' ' MRPS30,MRPL48,MRPS33'
cell2
'R-HSA-3000171:R-HSA-3000171' 'TTR'
'R-HSA-5655302:R-HSA-5655302' 'FGF1,FGF17'
cell3
'R-HSA-3000171:R-HSA-3000171' 'COL4A6,LAMA1,COL4A5'
'R-HSA-416482:R-HSA-416482' 'GNB2,ARHGEF16,ABR'
cell4
'R-HSA-3000171:R-HSA-3000171' 'COL11A2,COL3A1'
'R-HSA-5419276:R-HSA-5419276' 'MRPL1'
Iwanted_output:
采纳的回答
Stephen23
2018-12-14
编辑:Stephen23
2018-12-14
Use ismember in a loop:
C0 = {'A';'B';'C';'D';'F'}; % your 600x1 cell array.
C1 = {'A',1;'C',123;'X',0};
C2 = {'B',21;'D',2222};
C3 = {'C',321;'F',333333;'A',111111};
C4 = {'C',444};
CN = {C1,C2,C3,C4}; % all inputs in one cell array.
CZ = cell(numel(C0),numel(CN)); % preallocate output array.
for k = 1:numel(CN)
[idx,id0] = ismember(CN{k}(:,1),C0);
CZ(id0(idx),k) = CN{k}(idx,2);
end
7 个评论
Jan
2018-12-14
编辑:Jan
2018-12-14
@chocho: Your question was: "I want to output a cell of size 600*4 with the 600 rows and 4 columns". This sounds clearly as 4 columns, not 5.
So you want to add C0 as first column? Easy:
CZ = cat(2, C0, CZ)
Or modify the code:
CZ = cell(numel(C0), numel(CN) + 1); % preallocate output array.
CZ(:) = {0}; % Or {'0'} or {'[]'} or whatever you want
CZ(:,1) = C0;
for k = 1:numel(CN)
[idx, id0] = ismember(CN{k}(:,1), C0);
CZ(id0(idx), k + 1) = CN{k}(idx, 2);
end
Stephen23
2018-12-14
"i was thinking that you will do these 2 things inside your code inside the for loop "
Yes, you could also do that, that is a good idea. It might even be more efficient and/or simpler to do those steps inside the loop.... you should give it a try.
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