Generate same random permutations (reshape) for sequence?

2018 12 17
1 个回答
更新时间：2018 12 18
3 次查看（30 天）

0 个投票

I amlooking for a way genrate random permutation function for X and Y.
Example:
X = randi ([0 1], 10,1);
Y = bsc(A, 0.05);
If I reshape the data
reshape([X;Y],1,[]);
0 0 0 1 0 0 0 0 1 0 1 0 0 0 1 0 1 0 1 0
but here I want X Y reshape row wise
like
0 0
0 1 ....etc
Someone could help me.

请先登录，再回答此问题。

回答（1 个）

madhan ravi
madhan ravi 2018-12-17

1 个投票

a=[0 0 0 1 0 0 0 0 1 0 1 0 0 0 1 0 1 0 1 0];
reshape(a,2,[])'

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Barbossa H
Barbossa H 2018-12-17
Whenever I apply random permutation like,
random_X = X(randperm(size(X, 1)), :), random_Y = Y(randperm(size(Y, 1)), :)
it gives me different bit position of X and Y. but I want to apply random permutation condition for both X and Y.
Example: X (bit Position) Y (bit position)
5 5
9 9
1 1
thanks
Jan
Jan 2018-12-17
@Barbossa H: Do you mean:
index = randperm(size(X, 1));
random_X = X(index, :);
random_Y = Y(index, :)
madhan ravi
madhan ravi 2018-12-18
编辑：madhan ravi 2018-12-18
Thank you Jan , @Barbossa if you got the answer to your question make sure to accept the answer so that people know the question is solved.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Particle & Nuclear Physics 的更多信息

产品

版本

R2018b

标签

提问:

Barbossa H
Barbossa H
2018-12-17

编辑：

madhan ravi
madhan ravi
2018-12-18

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by