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Solve a numerical equation

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yinki23
yinki23 2019-1-28
回答： Torsten 2019-1-28
Hi everyone,
I have a problem solving a numerical equation. I want the result near zero for:
((1/6)*abs(sin(x*6/2)/sin(x/2))) = 1/sqrt(2)
It should be around x = 0.4695;
I tried the following:
myfunc = @(x) ((1/6)*abs(sin(x*6/2)/sin(x/2)))-1/sqrt(2);
x0 = 0;
fzero(myfunc,x0);
But somehow doesn't work for me. Can somebody help me please and tell me why it doesn't work?
Thanks.

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采纳的回答

Stephan
Stephan 2019-1-28
Hi,
use another x0:
myfunc = @(x) ((1/6)*abs(sin(x*6/2)/sin(x/2)))-1/sqrt(2);
x0 = 1;
fzero(myfunc,x0);
This will make it work.
Best regards
Stephan

更多回答（2 个）

madhan ravi
madhan ravi 2019-1-28
x0 = 1;
Torsten
Torsten 2019-1-28
x0 = 0 leads to a divison by zero since sin(x0/2) = sin(0) = 0

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