Merging the unique values
5 次查看(过去 30 天)
显示 更早的评论
final_result =
'Genes' 'T0&T2' 'T1&T3' 'T2&T4' 'T3&T5' 'T4&T6'
'YAR029W' 'dd' 'uu' 'dd' 'uu' 'du'
'YBL095W' 'du' 'ud' 'ud' 'du' 'du'
'YBL111C' 'uu' 'uu' 'ud' 'ud' 'du'
'YBL113C' 'uu' 'uu' 'uu' 'ud' 'ud'
'YBR096W' 'uu' 'uu' 'ud' 'ud' 'dd'
'YBR138C' 'ud' 'ud' 'ud' 'du' 'du'
In these i have to find the genes having same variable(1st variable in each interval) for all the intervals for example
'YAR029W'has 'd'(1st variable) in interval 'T0&T2' ,in same interval i want to find which genes havibg variable'd',for example
'YBL095W','YBR138C',has value 'd'('d' may be 1sy or 2nd variable )
Same should be done for 2nd gene also in interval 'T0&T2'
'YBL111C' has 1st value 'u',the genes having 'u' must be displayed where , 'YBL113C''YBR096W','YBR138C' must be displayed
So i need output as
'Gene1' 'T0&T2'
'YAR029W' 'dd'
'YBL095W' 'du'
'YBR138C' 'ud'
;
;
'Gene3' 'T0&T2'
'YBL111C' 'uu'
'YBL113C' 'uu'
'YBR096W' 'uu'
'YBR138C' 'ud'
;
;
I have 1000 genes please help
0 个评论
采纳的回答
Azzi Abdelmalek
2012-7-24
%i'm not sur if i've understood what you meant, but try this
a=final_result;[n,m]=size(a);B=a(2:end,1);
for k=2:m
A=a(2:end,k); C=[B A];
ent1={strcat('out',num2str(2*k-3)) char(a(1,k))};
ent2={strcat('out',num2str(2*k-2)) char(a(1,k))};
s{1,k-1} =[ ent1;C(cellfun(@(x)any(regexp(x,'d')),A),:)];
s{2,k-1}= [ ent2;C(cellfun(@(x)any(regexp(x,'u[u,d]')),A),:)];
disp(s{1,k-1});disp(s{2,k-1})
end
0 个评论
更多回答(3 个)
Andrei Bobrov
2012-7-23
编辑:Andrei Bobrov
2012-7-24
EDIT
final_result = {...
'Genes' 'T0&T2' 'T1&T3' 'T2&T4' 'T3&T5' 'T4&T6'
'YAR029W' 'dd' 'uu' 'dd' 'uu' 'du'
'YBL095W' 'du' 'ud' 'ud' 'du' 'du'
'YBL111C' 'uu' 'uu' 'ud' 'ud' 'du'
'YBL113C' 'uu' 'uu' 'uu' 'ud' 'ud'
'YBR096W' 'uu' 'uu' 'ud' 'ud' 'dd'
'YBR138C' 'ud' 'ud' 'ud' 'du' 'du' };
fr = final_result(2:end,1:2);
frd = fr(cellfun(@(x)any(ismember(x,'d'),2),fr(:,2)),:);
fru = fr(cellfun(@(x)strcmp(x(1),'u'),fr(:,2)),:);
out = [arrayfun(@(x)frd([1,x:end],:),(2:size(fru,1)-1)','un',0);...
arrayfun(@(x)fru([x:end],:),(1:size(fru,1)-1)','un',0)];
3 个评论
Jan
2012-7-23
I do not understand the format of your output. Should "out1", "out2" be separate variables? What are the "; ;" exactly - an [2 x 0] cell string?
Azzi Abdelmalek
2012-7-23
编辑:Azzi Abdelmalek
2012-7-23
combining with Andrei answer:
a=final_result;[n,m]=size(a);B=a(2:end,1);
for k=2:m
A=a(2:end,k);
s{1,k-1} = [ [char(a(1,k)) '/gen1']; B(cellfun(@(x)any(regexp(x,'d')),A),:)];
s{2,k-1}= [[char(a(1,k)) '/gen3'] ;B(cellfun(@(x)any(regexp(x,'u[u,d]')),A),:)];
disp(s{1,k-1});disp(s{2,k-1})
end
per isakson
2012-7-24
编辑:per isakson
2012-7-24
This code
for ii = 2 : 6
out = cell(0,2);
first_character = final_result{ ii, 2 }(1);
for jj = ii : 7
if ismember( first_character, final_result{ jj, 2 } )
out = cat( 1, out, final_result( jj, 1:2 ) );
end
end
out
end
prints
out =
'YAR029W' 'dd'
'YBL095W' 'du'
'YBR138C' 'ud'
out =
'YBL095W' 'du'
'YBR138C' 'ud'
out =
'YBL111C' 'uu'
'YBL113C' 'uu'
'YBR096W' 'uu'
'YBR138C' 'ud'
out =
'YBL113C' 'uu'
'YBR096W' 'uu'
'YBR138C' 'ud'
out =
'YBR096W' 'uu'
'YBR138C' 'ud'
>>
The columns
'T1&T3' 'T2&T4' 'T3&T5' 'T4&T6'
are confusing.
.
You write:
out2(2nd gene)
'YAR029W' 'dd'
'YBR138C' 'ud'
is that in accordance with your requirements?
2 个评论
per isakson
2012-7-24
编辑:per isakson
2012-7-24
I guessed that regarding the columns, but still not including them here would have made it easier to read the question.
You know, I cannot assign the result to out1, out2, etc. That would have made Jan and Walter very disappointed with me:) See the FAQ.
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!