Converting a base ten number into a base two number?

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Alex Wazevich
Alex Wazevich 2019-2-7
评论： Shunichi Kusano 2019-2-7
The number is 47.1875 in base ten, I need to write a script to convert this into base two. So far, I have written for before the decimal place:
x=47;
index=1;
base=2;
q=floor(x/base);
while q>0
q=x/base;
q=floor(q);
r=[rem(x, base)]
result(index)=r;
index=index+1;
x=q;
end
I am having a difficult time with the script for after the decimal place. Any help would be greatly appreciated!

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回答（2 个）

Stephen23
Stephen23 2019-2-7
编辑：Stephen23 2019-2-7
x = 47.1875;
% Integer part:
n = 1+fix(log2(x));
I = nan(1,n);
y = fix(x);
for k = n:-1:1
I(k) = fix(mod(y,2));
y = fix(y/2);
end
% Fractional part:
n = 12; % places after the radix point.
F = nan(1,n);
y = mod(x,1);
for k = 1:n
F(k) = fix(2*y);
y = mod(2*y,1);
end
% Output:
s = char([I,-2,F]+'0')
giving:
s = 101111.001100000000
Shunichi Kusano
Shunichi Kusano 2019-2-7
编辑：Shunichi Kusano 2019-2-7
Interesting. Another way to utilize your code. This is a kind of normalization. After calculation, the number of digits is restored.
x_raw = 47.1875;
index=1;
base=2;
n = 12; % places after the radix point.
x = double(x_raw) / double(base)^-n; % normalization
q=floor(x/base);
while q>0
q=x/base;
q=floor(q);
r=[rem(x, base)];
result(index)=floor(r);
index=index+1;
x=q;
end
res2 = reverse(insertAfter(num2str(result,'%1d'), n, '.')) % shifting "." n digits.
hope this helps.

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