In need of decreasing exponential smooth curve

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Abhinandana R
Abhinandana R 2019-2-10
评论： Abhinandana R 2019-2-10
u=0.3; pi=22/7; g=80;
l=20; d=10; p=1;
r=linspace(0,1,10);
m=tand(p)
a=(r-m*(d+l)).^-2-((r-m*l).^-2)
q=(pi*r.^4*g)/(8*u*l)
t=(2*u*q.*a)/(pi*m)
plot(r,t)
I need a decreasing smooth exponential curve. please help me

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Stephan
Stephan 2019-2-10
编辑：Stephan 2019-2-10
Your linspace call will lead to 10 results calculated in the interval of 0...1. If you leave the 10 away, the standard is 100 values, which gives a smoother curve:
u=0.3; g=80;
l=20; d=10; p=1;
r=linspace(0,1);
m=tan(p);
a=(r-m*(d+l)).^-2-((r-m*l).^-2);
q=(pi*r.^4*g)/(8*u*l);
t=(2*u*q.*a)/(pi*m);
plot(r,t)
You should also do not overwrite pi - it is a constant in Matlab - no need to define it.
Best regards
Stephan
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Stephan
Stephan 2019-2-10
编辑：Stephan 2019-2-10
what about
m=exp(p)
for the interval 0...1 it is a smooth decreasing curve. That is the desired result?

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