putting the answer in a matrices

Question

fyza affandi 2019-2-25

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https://ww2.mathworks.cn/matlabcentral/answers/446877-putting-the-answer-in-a-matrices

编辑： Jan 2019-2-25

I have matrix a. Then, I find which column in each row has number bigger than 1. The code is as below

a =
     5     0     0     0     0     0     0     0     0     0
     3     1     0     0     0     0     0     0     0     0
     1     2     0     0     0     0     0     0     0     0
     1     0     1     0     0     0     0     0     0     0
>> for cpart=1:size(a,1)
b=a(cpart,:);
row = find(b ~=0)
end
row =
     1
row =
     1     2
row =
     1     2
row =
     1     3

How can I put the row in a matrices ?(as shown below)

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Image Analyst 2019-2-25

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What are you going to do if you have row? Because I'm thinking you don't even need it and whatever you're going to do can be done much easier with a mask

mask = a~=0; % Create a logical 2-D matrix.

So I don't want to tell you how to get row if it just makes things more complicated for what you eventually want to do. So, what will you do with row if you had it?

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Answer 1

Jan 2019-2-25

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https://ww2.mathworks.cn/matlabcentral/answers/446877-putting-the-answer-in-a-matrices#answer_362667

编辑：Jan 2019-2-25

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With a loop:

nA     = (a ~= 0);
nRow   = size(a, 1);
nCol   = max(sum(nA, 2));
result = zeros(nRow, nCol);  % Pre-allocation
for c = 1:nRow
    v = find(nA(c, :));
    result(c, 1:numel(v)) = v;
end

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Answer 2

madhan ravi 2019-2-25

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 b=arrayfun(@(x)find(a(x,:)),1:size(a,1),'un',0);
 M=max(cellfun('prodofsize',b));
 C=cellfun(@(x)[x zeros(1,M-numel(x))],b,'un',0);
 Result=vertcat(C{:})