How to count the number of nonzero numbers in a row.

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jaah navi
jaah navi 2019-2-27
评论： madhan ravi 2019-2-27
I having a matrix A=[ 0 0 0 0 0.4 0 0 0.3;
0.1 0 0 0.7 0 0.2 0 0 0;
0 0 0.6 0 0 0 0 0.9]
I want to count the number of elements which is not equal to zero present in each row
the answer will be A=[2;
3;
2]
I tried with the command
D=(numel(A~=0),1)
But unable to get the result.Could anyone please help me on this.

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采纳的回答

KSSV
KSSV 2019-2-27
编辑：KSSV 2019-2-27
Read about nnz
A=[ 0 0 0 0 0.4 0 0 0.3;
0.1 0 0 0.7 0 0.2 0 0 ;
0 0 0.6 0 0 0 0 0.9] ;
[m,n] = size(A) ;
iwant = zeros(m,1) ;
for i = 1:m
iwant(i) = nnz(A(i,:)) ;
end
iwant

更多回答（1 个）

madhan ravi
madhan ravi 2019-2-27
No loops needed:
sum(A~=0,2)

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