Assignment has more non-singleton rhs dimensions than non-singleton subscripts

2019 3 4
1 个回答
更新时间：2019 3 5
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0 个投票

n=50;classes=9;deepth=103;for i=1 to 9; index=1;
btraindata{i,1}=zeros(n*n*(classes-1),1,2,deepth);
tbtraindata{i,1}(index,1,1,deepth)=trainclass{i}(k,:);
it is showing assignment has more non-singleton rhs dimensions than nons-singleton subscrits.
pls give me some solution.

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回答（1 个）

Jan
Jan 2019-3-4

0 个投票

You can check this by your own. Insert these lines:
size(tbtraindata{i,1}(index,1,1,deepth))
size(trainclass{i}(k,:))
% before this line:
tbtraindata{i,1}(index,1,1,deepth)=trainclass{i}(k,:)
You will see, that the dimensions do not match. At least one of them is not, what it should be. The readers cannot guess, which one is correct.

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