A simple question about undefined function error
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Hello,
Before i ask my question i want to mention that i am beginner level in matlab.
I wrote in matlab a simple program which is given below:
function [ output_args ] = Untitled( input_args )
for i=1:6
for j=1:30
k=1:24;
if 6<=k<17
if ruzgaruretimi(k,j)>sulamagider(k,j)
sebekein==sebekein
elseif ruzgaruretimi(k,j)<sulamagider(k,j)
if sdepo>0
sebekein==sebekein
sdepo==sdepo-1
elseif sdepo==0
sebekein==sebekein+15.708
end
end
end
end
end
end
I defined all veriables but i still get this error message:
Undefined function 'ruzgaruretimi' for input arguments of type 'double'.
Error in dnm (line 6)
if ruzgaruretimi(k,j)>sulamagider(k,j)
How can i solve it?
regards
1 个评论
Jan
2012-7-31
Variables are assigned by "=", while "==" compares variables. sebekein==sebekein replies TRUE for all elements - I assume it is meaningless actually.
采纳的回答
Daniel Shub
2012-7-31
There are so many things wrong with your function that fixing the error you are getting is going to be of little value. If you are a beginner in MATLAB, you need to read the documentation. For example these lines:
k=1:24;
if 6<=k<17
% Do something
end
are not doing what you think they are doing.
更多回答（2 个）
Honglei Chen
2012-7-31
You need to make sure that the function ruzgaruretimi are on your path. It should also expect double inputs. If it does, try to do
rehash toolbox
to refresh your toolbox cache.
Wayne King
2012-7-31
0 个投票
Have you defined this variable inside the function? Having the variable in your MATLAB workspace is not sufficient.
You could declare ruzgaruretimi as a global variable, but I think it is probably better to either define it inside your function, or pass that variable to your function as an input argument.
1 个评论
Wayne King
2012-7-31
Sorry, if it is a function, then what Honglei suggested is correct. I may have misunderstood that ruzgaruretimi is a matrix. If it is a matrix, then you have to make it a global variable, define it inside the function, or pass it as an input argument.
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