Straight line from all points of A to every single point of B

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Riccardo Rossi
Riccardo Rossi 2019-3-12
编辑： Jan 2019-3-12
Hi everybody,
i have 2 array with different number of rows (with columns that indicate x, y and z):
A (3x3 duble)
2.5 6.6 9.5
1.6 6.6 2.8
2.6 0.9 1.8
B (4x3 duble)
2.4 6.7 9.8
2.6 6.9 7.8
2.9 7.7 5.8
3.4 8.8 4.8
I want to track the straight line which passes from all points of A to every single point of B. I made this script but it does not run:
[m,n]=size(B)
[o,p]=size(A)
STR=-20:.01:20;
for i = 1:m
C{i}=repmat(A(1:o,:),length(STR),1)'+((B(i,:))-A(1:o,:))'*STR;
end
How can i do it? Thank you!
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Riccardo Rossi
Riccardo Rossi 2019-3-12
编辑：Riccardo Rossi 2019-3-12
Thank you for the answer. I would like to obtain something like this:
C{1,1}=repmat(A(1,:),length(STR),1)'+((B(1,:))-A(1,:))'*STR;
C{1,2}=repmat(A(1,:),length(STR),1)'+((B(2,:))-A(1,:))'*STR;
C{1,3}=repmat(A(1,:),length(STR),1)'+((B(3,:))-A(1,:))'*STR;
C{1,4}=repmat(A(1,:),length(STR),1)'+((B(4,:))-A(1,:))'*STR;
C{1,5}=repmat(A(2,:),length(STR),1)'+((B(1,:))-A(2,:))'*STR;
C{1,6}=repmat(A(2,:),length(STR),1)'+((B(2,:))-A(2,:))'*STR;
C{1,7}=repmat(A(2,:),length(STR),1)'+((B(3,:))-A(2,:))'*STR;
C{1,8}=repmat(A(2,:),length(STR),1)'+((B(4,:))-A(2,:))'*STR;
C{1,9}=repmat(A(3,:),length(STR),1)'+((B(1,:))-A(3,:))'*STR;
C{1,10}=repmat(A(3,:),length(STR),1)'+((B(2,:))-A(3,:))'*STR;
C{1,11}=repmat(A(3,:),length(STR),1)'+((B(3,:))-A(3,:))'*STR;
C{1,12}=repmat(A(3,:),length(STR),1)'+((B(4,:))-A(3,:))'*STR;

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采纳的回答

Jan
Jan 2019-3-12
编辑：Jan 2019-3-12
With some guessing:
nB = size(B, 1)
nA = size(A, 1)
STR = -20:.01:20;
n = numel(STR);
C = cell(1, nA * nB);
iC = 0;
for iA = 1:nA
for iB = 1:nB
iC = iC + 1;
C{iC} = repmat(A(iA,:), n, 1).' + (B(iB, :) - A(iA, :)).' * STR;
end
end
As far as I can see, you can omit the repmat in Matlab >= 2016b.

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