Error using table (line 253) All variables must have the same number of rows.

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i don't know why there's an error with my table. all varibales have 25 values.
here's my code
step= (0.0:0.2:5)';
Psi0= psiO(:,1)';
Psi1= psiO(:,6)';
Psi2= psiO(:,11)';
Psi3= psiO(:,16)';
Psi4= psiO(:,21)';
Psi5= psiO(:,26)';
table(step,Psi0,Psi1,Psi2,Psi3,Psi4,Psi5)
  3 个评论
Ali Mulhi
Ali Mulhi 2019-3-15
i examined all my values in the table. They all have 25 values. i don't know what's wrong?!

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采纳的回答

KSSV
KSSV 2019-3-15
编辑:KSSV 2019-3-15
The first input is a column and rest are rows..so the error. Try:
table(step,Psi0',Psi1',Psi2',Psi3',Psi4',Psi5')
You need to rethink on your code. The initilaization and calling th eindices is not good.
  3 个评论
KSSV
KSSV 2019-3-15
It is not strange.......either you should input all rows or columns.....in my case I used all columns.
YOu have transposed the first input to a row from columna nd rest all are rows....

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更多回答(1 个)

Peter Perkins
Peter Perkins 2019-3-15
Psi0 = array2table(psi0(:,[1 6 11 16 21 16])
would have been helpful for this. And then addvars to add step at the beginning.
  2 个评论
Guillaume
Guillaume 2019-3-15
编辑:Guillaume 2019-3-15
or
[table(step), array2table(psi0(:,[1 6 11 16 21 16]))]
Either of these is a lot simpler than temporary numbered (!) variables.
Is there any difference between addvars and table concatenation?
Peter Perkins
Peter Perkins 2019-3-18
addvars lets you add new variables in the middle. It's really the only reason why it even exists.

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