Short way to write this function?
显示 更早的评论
Hello,
Does anyone know of a solution to this problem?
function[y]=rayleigh_product(x,x2,x3,x4) % For up to 55 storm steps (threshold = 4 in the original case)
global SDSRp_ Tz_Tz_
y=(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,1))^2))^(10800/Tz_Tz_(x4,2))...
*(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,2))^2))^(10800/Tz_Tz_(x4,3))...
*(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,3))^2))^(10800/Tz_Tz_(x4,4))...
*(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,4))^2))^(10800/Tz_Tz_(x4,5))...
*(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,5))^2))^(10800/Tz_Tz_(x4,6))...
*(1-exp(-0.5*(x/SDSRp_(x2,x3,x4,6))^2))^(10800/Tz_Tz_(x4,7))...
And it goes on till 55 parts. The code works now, but it would be useful to have the option of just doing the product of any number of functions. I.e, if I want to do the same analysys with a different data set.
采纳的回答
Walter Roberson
2019-3-19
编辑：Walter Roberson
2019-3-19
y = prod(arrayfun(@(IDX) 1-exp(-0.5*(x./SDSRp_(x2,x3,x4,IDX).^(10800./Tz_Tz_(x4,IDX+1)))), 1:55));
This assumes that SDSRp_ and Tz_Tz_ are functions. If they were arrays then there is more potential for vectorization.
Is it practical to rewrite the two functions to accept a vector for the last parameter?
3 个评论
José Antonio Torres
2019-3-19
Walter Roberson
2019-3-19
prod((1-exp(-0.5 *(x./SDSRp_(x2, x3, x4, 1:55)))).^(10800./Tz_Tz_(x4,1+(1:55))))
I think I had some brackets in the wrong place before.
José Antonio Torres
2019-3-19
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
