removing ticks
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If I use
set(gca,'xtick',[])
the ticks vanish as expected, but the exponent, common for all ticks, remains in the plot at the end of the axis.
How can I avoid this
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Friedrich
2011-4-1
Hi Hans,
now I get it. In this special case you have to deactivate the xticklabels, too. This should works fine:
A(1,1:21)= 100000:100020;
B(1:100,1)= 1:100;
C(1:100,1:21)=33;
figure;
pcolor(A,B,C)
set(gca,'xtick',[])
set(gca,'xticklabel',[])
Best regards,
Friedrich
更多回答(12 个)
Friedrich
2011-4-1
Hi Hans,
which MATLAB and Operating System are you using? I ask this because the following code works fine for me in R2010b and Win7 64bit:
>> nn2 = 1.0e-156*[ 1 2];
>> plot(nn2)
>> set(gca,'YTick',[])
Best regards,
Friedrich
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Friedrich
2011-4-1
Hi Hans,
could you please post a working code? Because I am not able to reproduce your problem. Under Win7 64bit and R2009a the following code work fine:
>>n = 6;
>>r = (0:n)'/n;
>>theta = pi*(-n:n)/n;
>>X = r*cos(theta);
>>Y = r*sin(theta);
>>C = r*cos(2*theta);
>> pcolor(X*1e-4,Y*1e-4,C)
>> set(gca,'XTick',[])
So it must be related to your code.
Friedrich
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Jan
2011-4-1
A workaround:
A(1,1:21)= 100000:100020;
B(1:100,1)= 1:100;
C(1:100,1:21)=33;
figure;
ax = axes('XTick', [], 'nextplot', 'add');
pcolor(ax, A,B,C)
set(ax, 'YLim', [min(B), max(B)]);
David
2011-8-19
I found this elsewhere.
1 vote Kelly Kearney answered 17 days ago Change the renderer from OpenGL to zbuffer.
set(gcf, 'renderer', 'zbuffer');Why this fixes the problem, I really have no idea. But I encounter it a lot when I add dateticks to my axes. Not sure if it's intended behavior or a bug, but most renderers eliminate the factor when manual tick labels are added; OpenGL does not (or at least doesn't always).
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Aurelien Queffurust
2014-3-5
I confirm this solution allows to removes exponent on my Windows 64-bit
Greg
2015-11-18
I realize this is a pretty old thread, but I think I've figured out what might have been causing a lot of the confusion in there after running into this issue myself...
Basically, the "opengl" renderer in older versions of MATLAB seems to have a bug that, when a custom XTickLabel is set, the axis exponent is still displayed. This does bug does not appear to happen with the "zbuffer" or "painters" Renderers.
The size of the "B" matrix matters because when you add a very large graphics object to a plot, MATLAB automatically switches the renderer over to opengl (presumably because of the better performance vs. painters or zbuffer).
So, when you execute this code in R2011b, you get no exponent on the axis:
figure
plot(1e6*(1:10),rand(10))
set(gca,'XTickLabel',{'a','b'})
But then if you flip the renderer to opengl, the exponent will appear:
set(gcf,'Renderer','opengl')
You can get rid of it again by going back to painters or zbuffer:
set(gcf,'Renderer','zbuffer')
set(gcf,'Renderer','painters')
I've tested this in R2011b (where the described issue exists) and in R2015a (where it does not), both on 64-bit Windows.
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the cyclist
2011-4-1
Can you give a simple example of code that exhibits this problem, because I am not seeing that behavior. For example, does this code
figure
plot(10.^(1:10),1:10)
set(gca,'XTick',[])
leave the exponent remaining? It does not for me.
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hans
2011-4-1
4 个评论
Jan
2011-4-1
The exponent string looks different for these two methods: For the bigger matrix, the exponent is set above the base number, while for the smaller the exponent is set to the right top. It seems like the strings are created by different methods depending on the number of YTicks! And only one method has the bug.
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