Why is plot(x,y=0) not giving a line at y=0?

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Shaona Bose
Shaona Bose 2019-4-4
编辑： madhan ravi 2019-4-4
I am trying to plot a function with a line through y=0 too.
I wrote this code:
x=0:0.01:10*pi;
plot(x,2*sin(x).*exp(-x/4));
hold on
y=0;
plot(x,y)
This is only giving me a curve and no line through y=0.
I am getting the y=0 line with this code:
x=0:0.01:10*pi;
plot(x,2*sin(x).*exp(-x/4));
hold on
y=zeros(length(x));
plot(x,y)
So what is happening with the pervios code? Doesnt y=0; make any sense here?

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采纳的回答

madhan ravi
madhan ravi 2019-4-4
编辑：madhan ravi 2019-4-4
Stephen’s answer is the way I would do it but the explanation for the not satisfactory result of your code:
y=0;
You create a scalar and you try to plot it with x which is vector, it doesn't work like that in MATLAB you should have done
plot(x,zeros(size(x))) % this creates zeros as same size as x.

更多回答（1 个）

Stephan
Stephan 2019-4-4
编辑：Stephan 2019-4-4
Hi,
no need for this - since you are using R2018b you can take advantage of the yline function:
x=0:0.01:10*pi;
plot(x,2*sin(x).*exp(-x/4))
yline(0,'r--');
Best rregards
Stephan

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