How to recognize if there is in a character a point '.'?

5 次查看（过去 30 天）
johan
johan 2019-4-8
评论： madhan ravi 2019-4-8
Dear Matlab community,
Maybe somebody can help me with the following problem. For a project I would if there is a character a point '.' by scanning each element of the character by returning a true (1), false (0) as answer in an array. I tried the following:
xx='00-055.0'
isstrprop(xx,'punct')
ans =
1×8 logical array
0 0 1 0 0 0 1 0
At the moment it also shows e.g. '-', but is there a method to find explicitely the point '.'?
Thank you.
Regards

请先登录，再回答此问题。

采纳的回答

madhan ravi
madhan ravi 2019-4-8
编辑：madhan ravi 2019-4-8
contains(regexp(xx,'.','match'),'.')
%or
strcmp(regexp(xx,'.','match'),'.')
%or
cellfun(@(x)x=='.',regexp(xx,'.','match'))
Gives:
ans =
1×8 logical array
0 0 0 0 0 0 1 0
  4 个评论
显示 2更早的评论
Guillaume
Guillaume 2019-4-8
Well, then you don't need to use a regular expression engine to split a char vector into a cell array of individual characters
num2cell(xx)
will do the job faster.

请先登录，再进行评论。

更多回答（2 个）

Guillaume
Guillaume 2019-4-8
编辑：Guillaume 2019-4-8
Edit: I misunderstood the question. It's even simpler than what I initially wrote.
Simply:
xx == '.'
If you want to check multiple characters at once, e.g. . and +
ismember(xx, '.+')
--------
Original answer
Simply
contains(xx, '.')
or
any(xx == '.') %probably faster than contains but only work as long as you're searching just for one character
if wanting to check if any of several characters are in xx, e.g. . and +:
any(ismember(xx, '.+')) %are any character of xx member of the set .+ ?
  5 个评论
显示 3更早的评论

请先登录，再进行评论。

Adam
Adam 2019-4-8
编辑：Adam 2019-4-8
What is wrong with simply
xx == '.'
if xx is a char array rather than a string as it seems to be?

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by