Matlab iteration through excel rows
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Hello,
I have a problem for which I'm not finding a solution for now, so I decided to ask you.
I have a given Excel File with several columns and Rows. I only need the Columns where the names are defined and their values are stored.
After knowing which columns are the right ones, I want to iterate through every row of these columns to extract the values. Can you may help me? Here is my Code for now.
filename = 'example.xls';
excelSheet = 'example';
columnFirst = {'A1','B1','C1','D1','E1','F1','G1','H1','I1','J1','K1','L1'};
columnName = 'Name';
columnNameLetter = '';
columnDefault = 'Default';
columnDefaultLetter = '';
n = 13;
for i=1:n
[~,text] = xlsread(filename,excelSheet,columnFirst{i});
if(strcmp(columnName,text))
columnNameLetter = columnFirst{i};
end
if(strcmp(columnDefault,text))
columnDefaultLetter = columnFirst{i};
end
end
I'm getting the result that the Names are in column G and their values in column L
Now how can I iterate through all the rows to extract the values?
2 个评论
Guillaume
2019-4-10
Bit of advice
columnFirst = {'A1','B1','C1','D1','E1','F1','G1','H1','I1','J1','K1','L1'};
n = 13;
for i = 1:n
So, whenever you change the list of column, you also have to change n to match the number of elements, AND you have to make sure that you've counted them correctly. Forget to change n, or put the wrong value and you've got a bug.
Why not let matlab determine the number of elements and avoid the risk altogether. It's also less work:
columnFirst = {'A1','B1','C1','D1','E1','F1','G1','H1','I1','J1','K1','L1'};
for i = 1:numel(columnFirst)
You should never hardcode the size of inputs, always let matlab find it out for you.
Florian Azemi
2019-4-10
采纳的回答
Guillaume
2019-4-10
It sounds like your spreadsheet has a row header and you want to find the columns with a particular header. That can be trivially achieved with readtable:
data = readtable('example.xlsx', 'Sheet', 'example', 'Range', 'A:L');
data.Name %return the content of the Name column
data.Default %return the content of the Default column
I would recommend that you keep all the data in the table and use . indexing to access the columns as you need them. There is no need to extract them into individual variables
name = data.Name; %no point to that. Simply use data.Name everywhere
更多回答（2 个）
Alex Mcaulley
2019-4-10
Try this, is that you want?
filename = 'example.xls';
excelSheet = 'example';
columnName = 'Name';
columnDefault = 'Default';
[~,~,raw] = xlsread(filename,excelSheet);
try
names = raw(2:end,contains(raw(1,:),columnName));
catch
names = [];
end
try
defaults = raw(2:end,contains(raw(1,:),columnDefault));
catch
defaults = [];
end
4 个评论
Florian Azemi
2019-4-10
Alex Mcaulley
2019-4-10
Can you upload your excel? It is difficult to know what is happening. What is the result of running this?
contains(raw(1,:),columnName)
contains(raw(1,:),columnDefault)
I'm not seeing the points of the try...catch statements. The lines in the try can never error* anyway so the catch will never be invoked.
Also note that contains is not the same as strcmp. contains(x, 'Name') returns true if x is for example 'a rose by a any other Name', strcmp only returns true for 'Name'.
So, overall the code should be:
filename = 'example.xls';
excelSheet = 'example';
columnName = 'Name';
columnDefault = 'Default';
[~, ~, raw] = xlsread(filename,excelSheet);
name = raw(2:end, strcmp(raw(1, :), columnName));
defaults = raw(2:end, strcmp(raw(1, :), columnDefault));
*edit: well, they can error if the 1st row does not contain text, but in that case, you'd be better off knowing than just ignoring the problem.
Alex Mcaulley
2019-4-10
编辑：Alex Mcaulley
2019-4-10
Florian Azemi
2019-4-10
编辑：Florian Azemi
2019-4-10
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