# Write a function called get_distance that accepts two character vector inputs representing the names of two cities. The function returns the distance between them as an output argument called distance. For example, the call get_distance('Seattle, WA'

39 次查看（过去 30 天）
Abhishek singh 2019-4-17

function distance = get_distance(x,y)
[~,~,raw] = xlsread('Distances.xlsx');
col_labels = raw(1,:);
row_labels = raw(:,1);
try
distance = raw{contains(row_labels,y),contains(col_labels,x)};
catch
distance = -1;
end
end
error
Assessment result: incorrectNashville, TN and Las Vegas, NV
Variable distance has an incorrect value.
Assessment result: incorrectRandom city pairs
Variable distance has an incorrect value.
get_distance('Chattanooga, TN','Meads, KY') returned -1 which is incorrect.

### 回答（22 个）

Arafat Roney 2020-5-6
function distance=get_distance(a,b)
[~,~,raw]=xlsread('Distances.xlsx');
row=raw(1,:);
col=raw(:,1);
for ii=2:length(row)
if strcmp(row(ii),a)
mii=ii;
break;
end
end
for jj=2:length(col)
if strcmp(col(jj),b)
njj=jj;
break;
end
end
if (strcmp(row(ii),a))&&(strcmp(col(jj),b))
distance=raw{mii,njj};
else
distance=-1;
end
end
##### 6 个评论显示 5更早的评论隐藏 5更早的评论

Mati Somp 2020-10-6
one more
function distance = get_distance(A,B)
[data txt] =xlsread('Distances.xlsx');
ii=0;
jj=0;
for i=2:length(data)
if string(A)==string(txt{1,i})
ii=i;
end
if (string(B)==string(txt{1,i}))
jj=i;
end
end
if (~(jj) || ~(ii))
distance=-1;
else
distance=data(ii-1,jj-1);
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Kulko Margarita 2021-2-12
I wish this code was commented. I understand the general idea, but would like to see the logic flow of whoever wrote it.

Olel Arem 2020-5-1

function distance=get_distance(city_1,city_2)
n=0;m=0;
[value,name]=xlsread('Distances.xlsx');
for ii=1:size(name,2)
if (strcmp(city_1,name(ii,1)))
n=ii;
end
end
for jj=1:size(name,1)
if (strcmp(city_2,name(1,jj)))
m=jj;
end
end
if(n==0 && m==0 && n==1&&m==1)
distance =-1;
elseif (n>0&&m>0)
distance=value(n-1,m-1);
else
distance=-1;
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Rik 2022-3-16
That will never be true. n can't be 0 and 1 at the same time. Why this uncommented block of code ever received an upvote is not clear to me.

Taif Ahmed BIpul 2020-5-28
function distance=get_distance(A,B)
[~,~,All]=xlsread('Distances.xlsx');
p=strcmp(All,A);
q=strcmp(All,B);
r=sum(p(:));
s=sum(q(:));
if ~(r==2&&s==2)
distance=-1;
return
end
a=find(p==1);
b=find(q==1);
distance=All{(a(1)),(b(1))};
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Walter Roberson 2020-7-20
The ==2 does not make sense to me; it would make sense to me if it were ==1 meaning that exactly one column matched.
Oh wait... the Raw (third) output has the names in the first row and in the first column. The person who wrote the above code assumes that each name will appear exactly once in the header row and once in the header column, for a total of two appearances: that is why the 2. The person also assumes that the order is exactly the same between the rows and columns.
Distance matrices should not be assumed to be symmetric. I would not recommend this version of the code.

UJJWAL Padha 2020-6-11
function distance = get_distance(x,y)
k=-1;
[~,~,all] = xlsread('Distances.xlsx');
[r c] = size(all)
for i = 1:r
for j = 1:c
if i==1 && j==1
continue;
else
if strcmp(x,all(i,1))==1 && strcmp(y,all(1,j))==1
k= all{i,j};
end
end
end
end
distance = k;
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Rik 2020-9-1
It turns out you can't reliably cheat off this page, because some solutions have bugs or flaws. If that weren't the case I would probably be a lot more active in deleting answers.

Ankit singh chauhan 2020-11-29

function distance=get_distance(city1,city2) [~,~,raw]=xlsread('Distance.xlsx') try s=strcmp(raw,city2)
g=strcmp(raw,city1)
[r1,c1]=find(s==1)
[r2,c2]=find(g==2)
distance=raw{r1,r2}
catch
distance=-1
end
##### 1 个评论显示 无隐藏 无
Rik 2020-11-29
Still the same question: why did you post this? What does it teach?

function distance = get_distance(a,b)
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
if strcmp(text{i,1}, a)
break
end
end
if i>=size(raw,1)
distance=-1;
else
for j=2:size(raw,2)
if strcmp(text{1,j}, b)
distance=raw{i,j};
break
end
end
if j>=size(raw,2)
distance = -1;
end
end
##### 13 个评论显示 12更早的评论隐藏 12更早的评论
Walter Roberson 2021-2-17
For this particular homework problem, the reference data has been defined to be stored in a xlsx file that has the format
<empty> <cityname1> <cityname2> <cityname3> ...
<cityname1> distance11 distance12 distance13 ...
<cityname2> distance21 distance22 distance23 ...
where the <cityname> are text such as 'Los Vegas, Nevada' and 'Wawa, Ontario', and the distances are numeric.
When you use xlsread on the file and ask for the second output, the output will be a cell array of character vectors, with the character vectors being present where the original data had text, and being empty where the original data had numbers. So it might look something like
txt = {
[], 'LA', 'Wawa', 'Lima'
'LA' [] [] []
'Wawa' [] [] []
'Lima' [] [] []
}
When you use txt{1,i} you would therefore be accessing the [] at the beginning, or one of the city names, 'LA', 'Wawa', 'Lima' -- you would be reading out of row #1 from the txt cell array. txt{ROWNUMBER, COLUMNNUMBER} is the general form.
Using string() on a character vector converts it from being a character vector to being a scalar "string" object. So the line
if string(A)==string(txt{1,i})
converts character vector inside A to a string() object; and then extracts the content of column #i from row 1 of the cell array named txt and converts that content into a string() object. Then the line uses == between the string objects.
The reason someone would do that is that == is defined between string objects to return true of the strings have the same content, and false if the strings do not have the same content, with false being returned if they are different because they have different lengths. So string('LA') == string('Wawa') is perfectly good code that will not have a problem.
But == is not defined between character vectors in the same way, In particular, == between character vectors will fail if they both have more than one character and the lengths do not match. 'LA'=='Wawa' would fail complaining that the array dimensions do not agree (meaning that the lengths are different.) To compare character vectors taking into account they might be different lengths, use strcmp(), as in strcmp('LA', 'Wawa')

Muhammad Sadiq 2020-5-7
function distance = get_distance(a,b)
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
if strcmp(text{i,1}, a)
break
end
end
if i>=size(raw,1)
distance=-1;
else
for j=2:size(raw,2)
if strcmp(text{1,j}, b)
distance=raw{i,j};
break
end
end
if j>=size(raw,2)
distance = -1;
end
end
##### 0 个评论显示 -1更早的评论隐藏 -1更早的评论

Alan Chacko 2020-5-13
function d = get_distance(c1,c2)
[~,~,city] = xlsread("Distances.xlsx");
[r,c] = size(city);
row = city(1:end,1);
col = city(1,1:end);
ccr=sort(contains(row(2:end),c1));
ccc=sort(contains(col(2:end),c2));
if ccr'==ccc
ir = find(strcmp(row,c1));
ic = find(strcmp(col,c2));
d = city{ir,ic};
else
d=-1;
end
##### 5 个评论显示 4更早的评论隐藏 4更早的评论
Walter Roberson 2020-5-31
What happens when you use the debugger to trace the flow of your code?

function distance=get_distance(L1,L2)
[n,~,r]=xlsread('matlab_dist.xlsx');
i=1;j=1;
[R C]=size(n);
while(~(strcmp(L1,r(1,i))) && i<=R)
i=i+1;
end
while(~(strcmp(L2,r(j,1)))&& j<=C)
j=j+1;
end
j=j-1;i=i-1;
if(~(strcmp(L1,r(1,i+1))) || ~(strcmp(L2,r(j+1,1))))
distance=-1;
else
distance=n(i,j);
end
end
##### 0 个评论显示 -1更早的评论隐藏 -1更早的评论

Ujjawal Barnwal 2020-6-7
function distance=get_distance(c1,c2)
[num txt raw]=xlsread("Distances.xlsx");
a=0;b=0;
for ii=2:337
if strcmp(txt{1,ii},c1)
a=ii;
elseif strcmp(txt{1,ii},c2)
b=ii;
end
end
if a && b
distance=num(a-1,b-1);
else
distance=-1;
end
##### 1 个评论显示 无隐藏 无
Walter Roberson 2020-6-7
Why 337?
Your code assumes that Distances contains data of a particular size. It also assumes that the number of rows and columns is the same. It further assumes that there is never a case where the two different cities happen to occur at the same row and column number. For example,
* apple orange grapefruit
orange 2 0 3
grapefruit 1 3 0
apple 0 2 1
Your code would fail for (say) orange, grapefruit because it assumes that when it finds orange in column 3, that it is not possible to also happen to find grapefruit in row 3.

Vishesh Haria 2020-6-7
function distance=get_distance(a,b)
[~,~,raw]=xlsread('Distances.xlsx');
row=raw(1,:);
col=raw(:,1);
for ii=2:length(row)
if strcmp(row(ii),a)
mii=ii;
break;
end
end
for jj=2:length(col)
if strcmp(col(jj),b)
njj=jj;
break;
end
end
if(njj > 0 && mii > 0)
distance = raw{mii,njj};
elseif(njj == 1 && mii == 1)
distance = -1;
elseif(njj == 0 && mii == 0)
distance = -1;
else
distance=-1;
end
end
Error:
distance = get_distance('g, WA','Miagmi, FL')
Unrecognized function or variable 'njj'.
Error in get_distance (line 19)
if(njj > 0 && mii > 0)
Help me understand this error.
##### 1 个评论显示 无隐藏 无

I think you might remove two elif condition commands and set default "mii" and "njj" as 0, then it could work.

Md Nazmus Sakib 2020-6-20
function y = get_distance(city_1,city_2)
global raw;
[~,~,raw] = xlsread('Distances.xlsx');
%fetching cities in rows
r_city = {};
for i = 1:337
r_city{1,i} = raw{1,i};
end
%fetching cities in columns
c_city = {};
for j = 1:337
c_city{1,j} = raw{j,1};
end
%searching city_1
search_c1 = strcmp(c_city,city_1);
%searching row
for ii = 1:337
if (search_c1(1,ii) == 1)
break
else
ii = 1;%if the city is not found ii will give 1
end
end
%searching city_2
search_c2 = strcmp(r_city,city_2);
%searching column
for jj = 1:337
if (search_c2(1,jj) == 1)
break
else
jj = 1;%if the city is not found jj will give 1
end
end
if ((ii == 1) || (jj == 1)) % if the city is not found
y = -1;
else
y = raw{ii,jj}(1,1);
end
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Md Nazmus Sakib 2020-6-21
Thanks, I think I'll first measure the size or length of 'raw'.

This works perfectly.
function distance = get_distance(city1,city2)
[~,~,raw] = xlsread('Distances.xlsx');
row = raw(1,:);
col = raw(:,1);
mi =0;mj =0;
for i = 2:length(row)
if strcmp(row(i),city1)
mi = i;
end
end
for j = 2:length(col)
if strcmp(col(j),city2)
mj = j;
end
end
if mi> 1 && mj>1
distance = raw{mi,mj};
else
distance = -1;
end
end
##### 3 个评论显示 2更早的评论隐藏 2更早的评论

Capulus_love 2020-8-12

function distance = get_distance(a,b)
[~,~,excel] = xlsread('Distances.xlsx');
col = excel(1,:);
row = excel(:,1);
x=size(col)
y=size(row)
col_count = 1;
row_count = 1;
for i = 2 : x(2)+1
col_count = col_count + 1;
if contains(col{i},a) == 1
break
end
end
for j = 2 : y(1)+1
row_count = row_count + 1;
if contains(row{j},b) == 1
break
end
end
if (col_count > 337) || (row_count > 337)
distance = -1
else
distance = excel{row_count,col_count}
end
end
% why Non-existent city is not solved...???
##### 3 个评论显示 2更早的评论隐藏 2更早的评论
Walter Roberson 2020-8-12
if (col_count > 337) || (row_count > 337)
What would happen if they changed the data file to one that had (for example) 500 cities?

Yan Li 2020-9-4
function distance = get_distance (ct1, ct2)
[~,~,raw]= xlsread("Distances.xlsx");
f_row = raw(1,:);
f_col = raw(:,1);
flag = false;
distance = -1;
for n=1:length(f_row)
for m=1:length(f_col)
if string(f_row(n)) == ct1 && string(f_col(m)) == ct2
flag = true
distance = raw{n,m};
end
end
end
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Rik 2020-9-4
Surprisingly enough this works.
string({'foo'})=='foo'
Why did you decide to post this? What does it teach?
Also, why are you setting a flag, but not returning it or using it anywhere?

Ahmed Saleh 2021-3-28

function distance = get_distance(city1,city2)
[~,~,distances] = xlsread('Distances.xlsx');
num1=0;
num2=0;
s=size(distances);
for i=2:s(1)
logic=strcmp(city1,distances{i,1});
if logic== true
num1=i;
break
end
end
for j=2:s(2)
logic2 = strcmp(city2,distances{1,j});
if logic2 == true
num2=j;
break
end
end
if num1==0 || num2==0
distance=-1;
return
end
distance=distances{num1,num2};
end
##### 7 个评论显示 6更早的评论隐藏 6更早的评论
Ahmed Saleh 2021-3-30
ok, thank you

Abhijeet Singh 2021-5-14

function distance = get_distance(x,y)
[~,~,everything] = xlsread('Distances.xlsx');
a = everything(1:size(everything,1),1);
b = everything(1,1:size(everything,2));
for j = 1:size(everything,1)
l=0;
if strcmp(a(j,1),x)
l=j;
break
end
end
for i = 1:size(everything,2)
k=0;
if strcmp( b(1,i),y)
k=i;
break
end
end
if k ~= 0 && l ~= 0
s = everything(l,k);
distance = s{1};
else
distance = -1;
end
end
##### 3 个评论显示 2更早的评论隐藏 2更早的评论
Rik 2021-5-15
What would you say is the key difference between your solution and the one above this one?
If you want to educate: comments are a great way to explain what your code is doing.
Also:
a = everything(1:size(everything,1),1);
b = everything(1,1:size(everything,2));
%is equivalent to this:
a = everything(:,1);
b = everything(1,:);

Silvana Castillo 2021-6-3
function distance = get_distance(c1,c2);
% reads excel file in just everything
[~,~,everything] = xlsread('Distances.xlsx');
% find would give index of c1 readinf first column
a = find(strcmp(everything(1,1:end),c1))
% find would give index of c2 reading first row
% strcmp = are equals two strings inputs?
b = find(strcmp(everything(1:end,1),c2))
% if any c1 or c2 do not exist
if isempty(a) || isempty(b)
distance = -1
else
% converts from cell class to matrix or double
%the distance value based on index
distance = cell2mat(everything(a,b))
end
##### 0 个评论显示 -1更早的评论隐藏 -1更早的评论

Milad Mehrnia 2021-10-31
function distance = get_distance(a,b)
[num,txt] = xlsread('Distances.xlsx');
x = 0;y = 0;
for i = 2:lenghth(txt)
if strcmp(txt{1,i},a)
x = i;break; % It's better to use break, Because it reduces the running time significantly
end
end
for j = 2:height(txt) % It's better to use a seperated for function for j, Because it reduces the running time significantly too
if strcmp(txt{j,1},b)
y = j;break;
end
end
if ~x || ~y
distance = -1;
else
distance = num(x-1,y-1);
end
##### 2 个评论显示 1更早的评论隐藏 1更早的评论
Milad Mehrnia 2021-11-1
As we have the matrices on the memory, you are right and ismember is better than for. After your comment I tried it and the result is awesome. It brakes the time to half.
Really thank you

Zia Ur Rehman 2022-8-30
Hi folks,
plz check my code and plz tell me if I can improve this.
function distance = get_distance(a,b)
[~, ~, data] = xlsread('Distances.xlsx'); %reading the file and having its full data that is by default raw data in data variable on 3rd aurgument
z = size(data); % Calculating the size as we need to traverse both first coloumn and first row
c = z(1,1); % c = no. of rows
d = z(1,2); % d = no. of coloumn
for i = 2:c % as (1,1) of file is empty so starting from 2 to the length of rows and coloumns
e = strcmp(data{1,i},a); % checking through first row and compare with a
if e == true % if we find the matching then record its index in f and stop the loop through 'break'.
f = i;
break;
end
end
for j = 2:d
k = strcmp(data{j,1},b); % checking through first coloumn and compare with b
if k == true % if we find the matching then record its index in l and stop the loop through 'break'.
l = j;
break;
end
end
if e==true && k==true % if both are true then show the distance at that index(f,l) otherwisr distance = -1
distance = data{f,l};
else
distance = -1;
end
##### 4 个评论显示 3更早的评论隐藏 3更早的评论
Zia Ur Rehman 2022-8-30
ok, I will check how this builtin function works.

Pascal 2023-6-15
I got this solution but the last bit of code seems rather plump, do you have suggestions to improve the code?
function [distance] = get_distance(c1,c2)
raw = readcell('Distances.xlsx');
row1 = raw(1,2:end);
col1 = raw(2:end,1);
ind1 = find(ismember(row1,c1));
ind2 = find(ismember(col1,c2));
if isempty(ind1) || isempty(ind2)
distance = -1;
else
dis = raw(2:end,2:end);
d = dis(ind1,ind2);
distance = cell2mat(d);
end

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