Can I arrange a double array into cell array based on discontinuity of values?

Question

Josh Hwa 2019-4-28

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/459008-can-i-arrange-a-double-array-into-cell-array-based-on-discontinuity-of-values

评论： Dyuman Joshi 2023-12-14

I have 1x15 double array defined as 'a' and I would like to make them classified into each cell column if the increment of value is broken. This is my code, I have no idea how to make a1 become a2. If the next value is not the prvious number, n+1, then it should break and create new cell column.

axis([0 30 0 30]);
hold on;
a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2={[1 2 3 4 5] [10 11 12 13] [18 19 20 21 22 23]} ;
cellfun(@(x) plot(x,x), a2);

The length is not fixed, it could be like this

a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2={[1 2 3 4 5 6 7 8 9 10 11 12 13] [18 19 20 21 22 23]} ;

or like this.

a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2={[1 2 3 4] [11 12 13] [18 19 20 21 22 23] [30 31 32 33] [40 41 42]};

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Answer 1

Voss 2023-12-14

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/459008-can-i-arrange-a-double-array-into-cell-array-based-on-discontinuity-of-values#answer_1371664

在 MATLAB Online 中打开

a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a2 = 1×3 cell array
    {[1 2 3 4 5]}    {[10 11 12 13]}    {[18 19 20 21 22 23]}
a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a2 = 1×2 cell array
    {[1 2 3 4 5 6 7 8 9 10 11 12 13]}    {[18 19 20 21 22 23]}
a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2 = split_vector(a1)
a2 = 1×5 cell array
    {[1 2 3 4]}    {[11 12 13]}    {[18 19 20 21 22 23]}    {[30 31 32 33]}    {[40 41 42]}
function out = split_vector(a)
d = diff(a);
n = diff(find([true, d>min(d), true]));
out = mat2cell(a,1,n);
end

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Dyuman Joshi 2023-12-14

在 MATLAB Online 中打开

Another method -

a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a2 = 1×3 cell array
    {[1 2 3 4 5]}    {[10 11 12 13]}    {[18 19 20 21 22 23]}
a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a2 = 1×2 cell array
    {[1 2 3 4 5 6 7 8 9 10 11 12 13]}    {[18 19 20 21 22 23]}
a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2 = split_vector(a1)
a2 = 1×5 cell array
    {[1 2 3 4]}    {[11 12 13]}    {[18 19 20 21 22 23]}    {[30 31 32 33]}    {[40 41 42]}
function out = split_vector(a)
idx = [find(diff(a)~=1) numel(a)];
out = mat2cell(a, 1, [idx(1) diff(idx)]);
end