Creating an array of strings for mapping indexes to values

16 次查看(过去 30 天)
In Python it is easy to implement but wondering how can we do it in MATLAB. Can someone trnslate this toi MATLAB code.
stationmap = [S0,S1,S2,S3,S4,S5,S6,S7,S8,S9]
for i in range(10000):
Station_ID = stationmap[i % 10]
print("For Time {0}, we have station {1}".format(i, Station_ID))
  1 个评论
Stephen23
Stephen23 2019-5-4
This is MATLAB, so you can easily get rid of the loop:
>> V = 1:10000;
>> C = {'S0', 'S1', 'S2', 'S3', 'S4', 'S5', 'S6', 'S7', 'S8', 'S9'};
>> T = [num2cell(V);C(1+mod(V-1,numel(C)))];
>> fprintf('For Time {%d}, we have station {%s}\n',T{:})
For Time {1}, we have station {S0}
For Time {2}, we have station {S1}
For Time {3}, we have station {S2}
For Time {4}, we have station {S3}
For Time {5}, we have station {S4}
For Time {6}, we have station {S5}
For Time {7}, we have station {S6}
For Time {8}, we have station {S7}
For Time {9}, we have station {S8}
For Time {10}, we have station {S9}
For Time {11}, we have station {S0}
... lots more lines here
For Time {9993}, we have station {S2}
For Time {9994}, we have station {S3}
For Time {9995}, we have station {S4}
For Time {9996}, we have station {S5}
For Time {9997}, we have station {S6}
For Time {9998}, we have station {S7}
For Time {9999}, we have station {S8}
For Time {10000}, we have station {S9}

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采纳的回答

Jan
Jan 2019-4-29
编辑:Jan 2019-4-29
What about:
stationmap = {'S0', 'S1', 'S2', 'S3', 'S4', 'S5', 'S6', 'S7', 'S8', 'S9'}
% Alternatively:
% stationmap = sprintfc('S%d', 0:9);
for k = 1:10000
fprint('For Time {%d}, we have station {%s}\n', ...
k, stationmap{mod(k, 10} + 1));
end
  1 个评论
altaf ahmed
altaf ahmed 2019-4-29
编辑:altaf ahmed 2019-5-4
stationmap = {'S0', 'S1', 'S2', 'S3', 'S4', 'S5', 'S6', 'S7', 'S8', 'S9'}
% Alternatively:
% stationmap = sprintfc('S%d', 0:9);
for k = 1:10000
fprintf('For Time {%d}, we have station {%s}\n', ...
k, stationmap{mod(k, 10) + 1});
end
Thanks a lot!!!!

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