If any element of the array is less than a number, do some statements

Question

Milan Basa 2019-5-5

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/460385-if-any-element-of-the-array-is-less-than-a-number-do-some-statements

评论： Walter Roberson 2019-5-7

采纳的回答： Walter Roberson

If any element of the array is less than a number, do some statements

I want to use this above thing in while loop

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Answer 1

Walter Roberson 2019-5-5

3
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/460385-if-any-element-of-the-array-is-less-than-a-number-do-some-statements#answer_373683

在 MATLAB Online 中打开

if any(YourArray(:) < TheValue)
    do the statements
end

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Milan Basa 2019-5-6

在 MATLAB Online 中打开

clc
clear all
lh=input('Enter the value of L/H ');
n2=input('Enter the value of N2 ');
re=input('Enter the value of Re ');
dt=input('Enter the value of dt ');
dx=input('Enter the value of dx ');
dy=input('Enter the value of dy ');
hd=input('Enter the value of H/d ');
e=input('Enter the stopping criteria ');
m=((lh*hd)/dx)+1;
n=(hd/dy)+1;
n1=n-n2;
v0=zeros(m,n);
v=zeros(m,n);
s0=zeros(m,n);
s=zeros(m,n);
v_v=zeros(m,n);
v_u=zeros(m,n);
it=1;
count=0;
e1=ones(m,n);
e2=ones(m,n);
e3=10;
while (any(e1(:)) > e) | (any(e2(:)) > e)
    count=count+1;
    dt1=it*dt;
    it=it+1;
    
c1=1/((1/dt1)+((2/re)*((1/(dx*dx))+(1/(dy*dy)))));
c2=1/(2*((1/(dx*dx))+(1/(dy*dy))));
for j=2:n1
    s(1,j) = -1;
end
for j=n1+1:n
    v(1,j) = 0;
    s(1,j) = ((j-1)*dy)-(hd);
end
for i=2:m-1
    s(i,1) = -1;
end
for j=2:n2
    s(m,j) = ((j-1)*dy)-1;
    v(m,j) = 0;
end
for j=n2+1:n
    s(m,j) = 0;
end
for i=2:m-1
    s(i,n) = 0;
end
    for i=2:m-1
        for j=2:n-1
            v(i,j) = c1*((v0(i,j)/dt1)-(v0(i,j+1)/(dy*dy))-(v0(i,j-1)/(dy*dy))+(v0(i+1,j)/(re*dx*dx))+(v0(i-1,j)/(re*dx*dx)));
            s(i,j) = c2*(((s0(i+1,j)+s0(i-1,j))/(dx*dx))+((s0(i,j+1)+s0(i,j-1))/(dy*dy))+v0(i,j));
        end
    end
    
    for j=2:n1
        v(1,j) = -2*((s0(2,j)-s0(1,j))/(dx*dx));
    end
    
    for i=2:m-1
        v(i,1) = 2*((s0(i,1)-s0(i,2))/(dy*dy));
    end
    
    for j=n2+1:n
        v(m,j) = -2*((s0(m-1,j)-s0(m,j))/(dx*dx));
    end
    
    for i=2:m-1
        v(i,n) = 2*((s0(i,n)-s0(i,n-1))/(dy*dy));
    end
    
    for i=1:m
        for j=1:n
            e1(i,j)=abs(v(i,j)-v0(i,j));
            e2(i,j)=abs(s(i,j)-s0(i,j));
            v0(i,j)=v(i,j);
            s0(i,j)=s(i,j);
        end
    end
    
    end
   
fprintf ('\n Iterations = %d \n \n',count)
disp (v)
disp (s)
for j=1:n1
    v_v(1,j) = 0;
    v_u(1,j) = 0;
end
for j=n1:n
    v_v(1,j) = 0;
    v_u(1,j) = 1;
end
for i=2:m-1
    v_v(i,1) = 0;
    v_u(i,1) = 0;
end
for j=1:n2
    v_v(m,j) = 0;
    v_u(m,j) = 1;
end
for j=n2:n
    v_v(m,j) = 0;
    v_u(m,j) = 0;
end
for i=2:m-1
    v_v(i,n) = 0;
    v_u(i,n) = 0;
end
for i=2:m-1
    for j=2:n-1
        
        v_u(i,j) = (s(i,j+1)-s(i,j-1))/(2*dy);
        v_v(i,j) = (s(i-1,j)-s(i+1,j))/(2*dx);
    end
end
disp (v_u)
disp (v_v)
figure (1);
plot (v_u);
figure (2);
plot (v_v);
startx=[1:1:m];
starty=[1:1:n];
figure (3);
quiver(v_u,v_v);
streamline(v_u,v_v,startx,starty);

This is the whole code.

I want every value of e1 and e2 to be less than e.

lh=1, n2=5 re=1 dt=0.1 dx=0.5 dy=0.5 hd=10 e=0.000001

Milan Basa 2019-5-7

Numerical SolutionMethodology.pdf

I'm following this pdf.

Walter Roberson 2019-5-7

Sorry, I am having problems with my vision, and that pdf is too much for me to go through in detail and compare to your code.

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If any element of the array is less than a number, do some statements

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If any element of the array is less than a number, do some statements

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