An accumulating matrix to be reset when the limit value is reached, the value being reset must be moved to another matrix

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Rune Kalhoej 2019-5-11

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https://ww2.mathworks.cn/matlabcentral/answers/461547-an-accumulating-matrix-to-be-reset-when-the-limit-value-is-reached-the-value-being-reset-must-be-mo

评论： Adam Danz 2019-5-13

采纳的回答： Rik

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Hello

can someone please help me with this challenge.

matrix

B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3]
A = cumsum (B);
A = [1, 5, 8, 9, 12, 14, 15, 15, 15, 16, 21, 27, 36, 37, 40]

Then i want A and C to act like this

A = [1, 0, 3, 4, 0, 2, 3, 3, 3, 4, 0, 0, 0, 1, 3] % Every time it exceds 5, the value has to be moved to C, and reset to 0
C = [0, 5, 0, 0, 7, 0, 0, 0, 0, 0, 9, 6, 9, 0, 0]

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Rune Kalhoej 2019-5-12

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primary loops, like this

clc
B = [5,3,4,7,8,6,3,2,1,0,3,2,7,8,3,4,2];
A = cumsum(B); %Dette er den matrice du vil sortere alt over 5
C = zeros(length(A),1); %Alle værdier over 5 fra Matrix matricen, bliver lagt over i denne, resten er 0.
for i = 1:length(A) 
    if A(i)>=5
        C(i) = A(i);
        A(i) = 0;     % den skal samtidig nulstilles , virker ikke :S
    else 
        C(i) = 0;
    end
end
table(A',C)

Adam Danz 2019-5-13

Duplicate

https://www.mathworks.com/matlabcentral/answers/461364-reset-value-in-cumsum-matrix-when-reachin-limit-and-move-the-value-to-another-matrix

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Answer 1

Rik 2019-5-12

3
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/461547-an-accumulating-matrix-to-be-reset-when-the-limit-value-is-reached-the-value-being-reset-must-be-mo#answer_374630

在 MATLAB Online 中打开

This should do the trick. Note that you should use numel to count the number of elements, not length, which is just doing max(size(A)). The difference is usually nothing, but it will trip you up at some point.

B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3];
A = cumsum (B);
C = zeros(size(A));
idx=find(A>=5);
while ~isempty(idx)
    idx=idx(1);
    C(idx)=A(idx);
    A(idx:end)=A(idx:end)-A(idx);
    
    idx=find(A>=5);
end
FormatSpec=[repmat('%d, ',1,numel(A)) '\n'];FormatSpec(end-3)='';
clc
fprintf(FormatSpec,A)
fprintf(FormatSpec,C)

Alternatively (which might be faster in some cases):

B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3];
A = cumsum (B);
C = zeros(size(A));
idx=find(A>=5);
while ~isempty(idx)
    idx=idx(1);
    C(idx)=A(idx);
    A=A-A(idx);
    
    idx=find(A>=5);
end
A=cumsum(B)-cumsum(C);%restore real A