How to remove the duplicate in the cell array but still keep the array structure?
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A={[3 11];[6 5 8];[ 11 5];[5]};
I wonder if there is any way to remove the duplicate numbers in A but still keep the dimension of the cell array? like
A={[3 11];[6 5 8];[];[]};
appreciate your time!
3 个评论
Kevin Phung
2019-5-14
how did
A={[3 11];[6 5 8];[ 11 5];[5]};
become
A={[3 11];[6 5 8];[];[]};
Hang Vu
2019-5-15
Jan
2019-5-15
@Hang Vu: You forgot to explain, which operation you want to apply. Why does "remove the duplicate in the cell array" produce the output for the shown input? Let me guess:
If a number occurs in an element of the cell, remove it from all subsequent elements.
采纳的回答
A = {[3 11];[6 5 8];[ 11 5];[5]};
for iA = 1:numel(A)
a = A{iA};
for jA = iA + 1:numel(A)
A{jA} = A{jA}(~ismember(A{jA}, a));
end
end
Or:
list = A{1};
for iA = 2:numel(A)
A{iA} = A{iA}(~ismember(A{iA}, list));
list = union(list, A{iA})
end
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