Hi everyone ! can anyone help me to do this , thank you

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% I'd like to take the first 4x4 block of X and put it in Xa and Xb
% in such a way as to take the first and second column of X and put it in the first and second column in Xa
% and take the third column and the fourth column of X and put it in the third and fourth column of Xb
% second block 4x4 of X
% the (5,6) column of X in the (5,6) column of Xa
% the (7,8) column of X in the (5,6) column of Xb
clear all
clc
P=2;
M=4;
X=rand(M,P*M);
Xa=zeros(M,P*M);
Xb=zeros(M,P*M);
  2 个评论
Fangjun Jiang
Fangjun Jiang 2019-5-14
编辑:Fangjun Jiang 2019-5-14
double check all the column numbers in your question and make sure they are correct.
mina massoud
mina massoud 2019-5-14
yes you are wright becasue at the end i need to make somthing like this for P=4:-
Xa(:,1:2)= X(:,1:2)
Xb(:,3:4)= X(:,3:4)
Xa(:,5:6)= X(:,5:6)
Xb(:,7:8)= X(:,7:8)
Xa(:,9:10)= X(:,9:10)
Xb(:,11:12)= X(:,11:12)
Xa(:,13:14)= X(:,13:14)
Xb(:,15:16)= X(:,15:16)
so can i do it with somthing more general , thank u

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采纳的回答

madhan ravi
madhan ravi 2019-5-14
编辑:madhan ravi 2019-5-14
[~,n]=size(X);
xai=[1:4:n,2:4:n];
xbi=[3:4:n,4:4:n];
Xa(:,xai)=X(:,xai)
Xb(:,xbi)=X(:,xbi)

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