remove zeros from sinc function

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Gaurav Sharma
Gaurav Sharma 2019-5-17
回答： Sulaymon Eshkabilov 2019-5-18
Hi there,
I am trying to observe the behaviour of the fourier trasform of the sinc function if some of its zeros will be removed. Normally, the sinc function will lead us to rectanglular function in fourier domain, but when I am trying to remove the zeros at 'pi' it is not showing anything due to NaN or infinite. May I request you to pls tell me how to deal with such problem?
Fs=42;Ts=1/Fs;
t=-1:Ts:40*Ts-Ts;
f=5;
y=sinc(t*f)/(1-5*t/(0.9)*pi);
figure;
plot(t,y);
xlabel('x');
ylabel(' magnitude');
fy=fft(y);%figure;
% plot(fy)
fy = fftshift(fy);figure;
plot([abs(fy)])%;angle(fy);real(fy);imag(fy)]','*')
  2 个评论
Jan
Jan 2019-5-17
编辑：Jan 2019-5-17
It is easier to read, if you include the code directly. Therefore I've copied it from the attachment.
"it is not showing anything due to NaN or infinite" - what is "it" here?
Gaurav Sharma
Gaurav Sharma 2019-5-18
"the plot"- is not showing any thing... no plot.... just blank screen

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采纳的回答

Sulaymon Eshkabilov
clearvars; close all
Fs=42;Ts=1/Fs;
t=-1:Ts:1;
f=5;
y=sinc(t*f)./(1-5*t/(0.9)*pi);
figure;
plot(t,y), xlabel('t'), ylabel(' y(t)'); title('Time domain analysis ')
L = length(t); Nblock = 256;
Y = fft(y, Nblock)/L;
f = Fs/2*linspace(0,2, Nblock/2+1);
figure;
plot(f, 2*abs(Y(1:Nblock/2+1))), title('Discrete FFT')
fY = fftshift(Y);figure;
plot(f, 2*abs(fY(1:Nblock/2+1))), title('Shift zero frequency')
figure, plot([angle(fY);real(fY);imag(fY)]','*')
title('Phase angle, Real & Imag components of Shift zero frequency')

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