How to Permute the array with specific number?
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I want to keep 1,2,6,7,9,10, they will not move
I have this array
b=[1,5,2,8,6,11,7,9,3,10]
P=perms(b);
HOw to use perms for 3,5,8,11 among 6 numbers above?
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采纳的回答
Stephen23
2019-5-29
>> b = [1,5,2,8,6,11,7,9,3,10];
>> idx = ~ismember(b,[1,2,6,7,9,10]);
>> mat = repmat(b,factorial(nnz(idx)),1);
>> mat(:,idx) = perms(b(idx))
mat =
1 11 2 8 6 5 7 9 3 10
1 11 2 8 6 3 7 9 5 10
1 11 2 5 6 8 7 9 3 10
1 11 2 5 6 3 7 9 8 10
1 11 2 3 6 8 7 9 5 10
1 11 2 3 6 5 7 9 8 10
1 8 2 11 6 5 7 9 3 10
1 8 2 11 6 3 7 9 5 10
1 8 2 5 6 11 7 9 3 10
1 8 2 5 6 3 7 9 11 10
1 8 2 3 6 11 7 9 5 10
1 8 2 3 6 5 7 9 11 10
1 5 2 11 6 8 7 9 3 10
1 5 2 11 6 3 7 9 8 10
1 5 2 8 6 11 7 9 3 10
1 5 2 8 6 3 7 9 11 10
1 5 2 3 6 11 7 9 8 10
1 5 2 3 6 8 7 9 11 10
1 3 2 11 6 8 7 9 5 10
1 3 2 11 6 5 7 9 8 10
1 3 2 8 6 11 7 9 5 10
1 3 2 8 6 5 7 9 11 10
1 3 2 5 6 11 7 9 8 10
1 3 2 5 6 8 7 9 11 10
6 个评论
Stephen23
2019-5-29
编辑:Stephen23
2019-5-29
Here is a simple but not-very-efficient solution (warning: generates all permutations and discards invalid ones) (note that 1 and 10 have been ignored to make the code simpler):
b = [5,2,8,6,11,7,9,3];
V = [2,6,7,9]; % fixed
P = perms(b);
[X,Y] = ismember(P.',V);
R = reshape(Y(X),[],size(P,1));
D = all(diff(R,1,1)>0);
Z = P(D,:)
Giving:
Z =
3 11 8 2 6 7 9 5
3 11 8 2 6 7 5 9
3 11 8 2 6 5 7 9
3 11 8 2 5 6 7 9
3 11 8 5 2 6 7 9
3 11 2 6 8 7 9 5
3 11 2 6 8 7 5 9
3 11 2 6 8 5 7 9
3 11 2 6 7 8 9 5
... lots of lines here
5 3 2 11 6 7 8 9
5 3 2 11 6 7 9 8
5 3 2 11 8 6 7 9
5 3 2 6 11 8 7 9
5 3 2 6 11 7 8 9
5 3 2 6 11 7 9 8
5 3 2 6 8 11 7 9
5 3 2 6 8 7 11 9
5 3 2 6 8 7 9 11
5 3 2 6 7 8 11 9
5 3 2 6 7 8 9 11
5 3 2 6 7 11 8 9
5 3 2 6 7 11 9 8
5 3 2 6 7 9 11 8
5 3 2 6 7 9 8 11
5 3 2 8 6 11 7 9
5 3 2 8 6 7 11 9
5 3 2 8 6 7 9 11
5 3 2 8 11 6 7 9
更多回答(1 个)
Jan
2019-5-28
编辑:Jan
2019-5-28
You did not mention how the output should look like. Perhaps:
b = [1,5,2,8,6,11,7,9,3,10];
keep = [1,2,6,7,9,10];
move = ~ismember(b, keep);
P = perms(b(move));
R = repmat(b, size(P,1), 1);
R(:, move) = P
6 个评论
Jan
2019-5-29
@Hang Vu: I do not understand, what you mean. You solved the problem, but this is another one? Is the problem of your question solved or not?
"if the moving numbers move then you will see the keeping move..." - what does this mean?
Please explain exactly, what you want to achieve.
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