Sorting a structure using Matlab2018
显示 更早的评论
Hi
I want to sort this structure in descensind order using MATLAB 2018:
ten.cat=[7,2,4,1].
I used the following commands but it is still not sorted:
pp_1=ten;
TT = struct2table(pp_1) % convert to tables
gg=sortrows(TT,'cat') % sort
sortedpp_1 = table2struct(gg) % convert the table back to structure.
please, help
3 个评论
What is your question and with which problem can we help you? What exactly is not sorted?
Why not sorting it by:
ten.cat = [7,2,4,1];
ten.cat = sort(ten.cat)
Guillaume
2019-5-29
@Jan, this should go as an answer as I see no way of improving on that with the information given.
@shamsuddeen, there's never any need to convert a structure to anything in order to operate on it. Certainly, converting a structure into a table and back is a complete waste of time for your purpose. In this case, the fact that ten is a structure is completely irrelevant anyway, you're not sorting a structure, but just one field of a scalar structure which is the same as any non-structure variable.
Shamsuddeen Abdullahi
2019-5-29
采纳的回答
Jan
2019-5-29
ten.cat = [7,2,4,1];
ten.cat = sort(ten.cat)
更多回答（1 个）
Simon Mählkvist
2019-5-29
编辑：Simon Mählkvist
2019-5-29
Hi,
Adjusting:
ten.cat=[7,2,4,1]
to:
ten.cat=[7;2;4;1]
gives what I think is the sought after results.
类别
在 帮助中心 和 File Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
